The solubility of silver sulfate (Ag2SO4), in moles per liter, can be expressed in terms of the resulting ion concentrations. Wh
ich relationship is correct?
1 answer:
Answer:
Solubility = [SO₄²⁻]
Explanation:
Solubility of Ag₂SO₄ can be understood seen its Ksp equilibrium:
Ag₂SO₄(s) ⇄ SO₄²⁻ + 2Ag⁺
<em>Where 1 mole of silver sulfate dissolves producing 1 mole of sulfate ion and 2 moles of silver ion.</em>
Solubility is defined as: "the amount of solid that can be dissolved per liter of solution".
In the dissolution process, the moles of Ag₂SO₄ dissolved are equal to moles of SO₄²⁻.
That means:
<h3>Solubility = [SO₄²⁻]</h3>
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