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Pani-rosa [81]
3 years ago
15

Traumatic brain injury. According to a report on traumatic brain injury, the force that a professional boxer's fist exerts on hi

s opponent's head is equivalent to being hit with a 5.9 kg bowling ball traveling at 8.9 m/s that stops in 0.018 s.
Determine the average force that the fist exerts on the head.

Physics
1 answer:
Anna11 [10]3 years ago
7 0

Answer: F = 2917.2N

Explanation: To solve the question, we will employ Newton 2nd law of motion.

After hitting, the ball stop and no rebound.

The force exert by the ball is equal to the average force the fist will exert on the head.

Please find the attached file for the solution

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As the Moon orbits Earth, its direction constantly changes. Which of these forces is most likely causing this change in velocity
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Gravity is the most likely force causing this phenomenon. please leave a thanks
8 0
3 years ago
How much work is done by 0.070 m3 of gas, when the volume remains constant with pressure of 63 x 105 Pa?
stealth61 [152]

Answer:

W = 0 J

Explanation:

The amount of work done by gas at constant pressure is given by the following formula:

W = P\Delta V

where,

W = Work done by the gas

P = Pressure of the gas

ΔV = Change in the volume of the gas

Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:

W = P(0\ m^3)\\

<u>W = 0 J</u>

5 0
3 years ago
14. a ball is thrown horizontally from the roof of a building 75 m tall with a speed of 4.6 m/s. a. how much later does the ball
Burka [1]

The time taken to hit the ground is 3.9 s, the range is 18m and the final velocity is 42.82 m/s

<h3>Motion Under Gravity</h3>

The motion of an object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.

Given that a ball is thrown horizontally from the roof of a building 75 m tall with a speed of 4.6 m/s.

a. how much later does the ball hit the ground?

The time can be calculated by considering the vertical component of the motion with the use of formula below.

h = ut + 1/2gt²

Where

  • Height h = 75 m
  • Initial velocity u = 0 ( vertical velocity )
  • Acceleration due to gravity g = 9.8 m/s²
  • Time t = ?

Substitute all the parameters into the formula

75 = 0 + 1/2 × 9.8 × t²

75 = 4.9t²

t² = 75/4.9

t² = 15.30

t = √15.3

t = 3.9 s

b. how far from the building will it land?

The range can be found by using the formula

R = ut

Where u = 4.6 m/s ( horizontal velocity )

R = 4.6 × 3.9

R = 18 m

c. what is the velocity of the ball just before it hits the ground?

The final velocity will be

v = u + gt

v = 4.6 + 9.8 × 3.9

v = 4.6 + 38.22

v = 42.82 m/s

Therefore, the answers are 3.9 s, 18 m and 42.82 m/s

Learn more about Vertical motion here: brainly.com/question/24230984

#SPJ1

7 0
1 year ago
A fire engine approaches a wall at 5 m/s while the siren emits a tone of 500 Hz frequency. At the time, the speed of sound in ai
Svetach [21]

Answer:

The  values is  f_b  =14.9 \  beats/s

Explanation:

From the question we are told that

   The  speed of the fire engine is  v =  5\ m/s

    The frequency of the tone is  f =  500 \ Hz

    The speed of sound in air is v_s  =  340 \ m/s

The  beat frequency is mathematically represented as

     f_b  =  f_a  -  f

Where  f_a is the frequency of sound heard by the people in the fire engine and is is mathematically evaluated as

   f_a  =  [\frac{v_s + v }{v_s  -v} ]* f

substituting values

  f_a  =  [\frac{340 + 5 }{340  -5} ]* 500

  f_a  = 514.9 \  Hz

Thus  

      f_b  =514.9 -  500

      f_b  =14.9 \  beats/s

8 0
3 years ago
Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te
QveST [7]

Answer:

Please see attachment

Explanation:

Please see attachment

8 0
3 years ago
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