When the pressure that a gas exerts on a sealed container changes from 22.5 psi to psi the temperature changes from 110 c to 65.
1 answer:
Gay- Lussacs law states that the pressure of a gas is directly proportional to temperature for a fixed amount of gas at constant volume.
therefore P/T = k
where P - pressure , T - temperature and k - constant
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 - temperature in kelvin - 110 °C + 273 = 383 K
T2 - 65.0 °C + 273 = 338 K
substituting these values in the equation
P = 19.9 psi
new pressure is 19.9 psi
therefore P/T = k
where P - pressure , T - temperature and k - constant
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 - temperature in kelvin - 110 °C + 273 = 383 K
T2 - 65.0 °C + 273 = 338 K
substituting these values in the equation
P = 19.9 psi
new pressure is 19.9 psi
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2F₂(g) + 2 H₂O(g) → O₂(g) + 4HF(g)
If we assume that all the gases are ideal gases, we can describe the coefficients of this reaction as Volume rather than moles, so we can apply the following equations:
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