Answer:
Both are the indicators which helps to identity the acid and base
Answer:
your simpal answer is 177.32
Answer:
8.0356 * 10^-5 moles of NaHCO3
Explanation:
Sulphuric acid = H2SO4
Sodium bicarbonate = NaHCO3
The reaction between both compounds is given by;
2NaHCO3(aq) + H2SO4(aq) → Na2SO4(aq) + 2CO2(g) + 2H2O(l)
In the reactin above;
2 mol of NaHCO3 neutralizes 1 mol of H2SO4
At stp, 1 mol occupies 22.4 L;
1 mol = 22.4 L = 22400 mL
x mol = 0.9 mL
x = 0.9 / 22400 = 4.0178 * 10^-5 moles of H2SO4
Since 2 mol = 1 mol from the equation;
x mol = 4.0178 * 10^-5
x mol = 2 * 4.0178 * 10^-5
x = 8.0356 * 10^-5 moles of NaHCO3
Answer:
Sodium hydroxide
Explanation:
Sodium hydroxide ( NaOH ) -
Sodium hydroxide is an inorganic compound , and is also called caustic soda and lye .
It is an ionic compound , which is white in color and is in solid state .
The cation and anion of this salt are the sodium cation Na⁺ and the hydroxide anions OH⁻ .
<u>It is highly basic in nature and is soluble in water , and when left open in air it can readily absorb moisture from the air , to form a hydrated sodium hydroxide .</u>
I literally is 1000 ml. Therefor 1.2 literally is 1.2*1000 which is 1200 ml
