Na is the reducing agent since it is being oxidized
c both of the above the oh ranges from 0 to 14 a ph of 7 is neutral
Answer:
C
Explanation:
The oxidation number of Sulphur in SO4^2- is;
x + 4(-2) = -2
x - 8 = -2
x = -2 + 8
x = 6
Now,
the oxidation number of sulphur in H2SO3 is
2 (1) + x + 3(-2) = 0
2 + x -6 = 0
-4 + x = 0
x = 4
Hence, the oxidation number of sulphur changed from +6 to +4 which signifies gain of two electrons as shown in option C.
Answer:
sorry can't read in spanish:/ can you please put it in english for me.
Mass and weight are two features used to describe matter
