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Vlad1618 [11]
2 years ago
6

A balloon is filled to a volume of 18.9L at a temperature of 27.1ºC. If the pressure in the balloon is measured to be 2.20 atm,

how many moles of gas are contained inside the balloon?
Chemistry
1 answer:
ryzh [129]2 years ago
4 0

<u>Answer:</u> The number of moles of gas in balloon is 1.69 moles

<u>Explanation:</u>

To calculate the number of moles of gas, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 2.20 atm

V = Volume of the gas = 18.9 L

T = Temperature of the gas = 27.1^oC=[27.1+273]=300.1K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of gas = ?

Putting values in above equation, we get:

2.20atm\times 18.9L=n\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 300.1K\\\\n=\frac{2.20\times 18.9}{0.0821\times 300.1}=1.69mol

Hence, the number of moles of gas in balloon is 1.69 moles

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Answer:

A.

Explanation:

The continents on Earth have a fixed position.

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How is density different from weight and mass?
defon

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How is density different from weight and mass you say? It's simple!

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1 year ago
Read 2 more answers
I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol
galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = \Delta H_f_{(I_2)}=62.438 kJ/mol

Enthalpy of formation of chlorine gas = \Delta H_f_{(Cl_2)}=0 kJ/mol

Enthalpy of formation of ICl gas = \Delta H_f_{(ICl)}=17.78 kJ/mol

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]

=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol

Enthaply change when 1.62 moles of iodine gas recast:

\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ

Entropy of the surrounding = \Delta S^o_{surr}=\frac{\Delta H}{T}

=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0
3 years ago
How many grams of hydrogen are needed to produce 1.80 g of water according to this equation? 2H2 + O2 → 2H2O
Arisa [49]

Hey there!:

Molar mass:

H2 = 2.01 g/mol    ;    H2O = 18.01

Given the reaction:

2 H2 + O2 = 2 H2O

2 * (2.01 ) g H2 ------------- 2 * ( 18.01 ) g H2O

mass H2 --------------------- 1.80 g H2O

mass H2 = 1.80 * 2 * 2.01 / 2* 18.01

mass H2 = 7.236 / 36.02

mass H2 = 0.2008 g


Hope that helps!

7 0
3 years ago
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