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kaheart [24]
3 years ago
5

Can someone help please

Chemistry
1 answer:
romanna [79]3 years ago
6 0

helllllo

hiiiiiiiii

ha

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How would the following solid substances be classified? The choices are metallic, ionic, or molecular. C6H12O6
Bumek [7]

Answer:

C₆H₁₂O₆ (glucose)

A molecular substance.

Explanation:

C₆H₁₂O₆ does not dissociate. It is not a ionic type.

There is no metal in the compound, it is not a metallic type.

Glucose is an organic molecule, a type of carbohidrate, the most common  from the monosaccharides type.

4 0
3 years ago
½O2(g) + H2(g) ⇌ H2O(g)
ira [324]

Answer:

-241.826 kJ·mol⁻¹;  -146.9 J·K⁻¹mol⁻¹; 664.6 J·K⁻¹mol⁻¹; spontaneous

Explanation:

                        ½O₂(g)   +  H₂(g) ⟶ H₂O(g)

ΔHf°/kJ·mol⁻¹:      0                0        -241.826

S°/J·K⁻¹mol⁻¹:   205.0         130.6       188.7

1. ΔᵣH

ΔᵣH = products -reactants = -241.826 -(0 + 0) = -241.826 kJ·mol⁻¹

2. ΔᵣS

ΔᵣS = products - reactants = 188.7 - (205.0 + 130.6) = 188.7 - 335.6 = -146.9 J·K⁻¹mol⁻¹

3. ΔS(univ)

\begin{array}{rcl}\Delta S_{\text{univ}} &=& \Delta S_{\text{sys}}  +\Delta S_{\text{surr}}\\\\ &=& \Delta S_{\text{sys}}  -\dfrac{\Delta H_{\text{sys}}}{T}\\\\& = & -146.9 - \dfrac{-241826}{298}\\\\& = & -146.9 + 811.5\\& = & \mathbf{664.6 \,\, J\cdot K^{-1}mol^{-1}}\\\end{array}

4. Spontaneity

\begin{array}{rcl}\Delta G &=& \Delta H - T\Delta S\\& = & -241.826 - 298 \times (-0.1469)\\& = & -241.826 + 43.776\\& = &  \textbf{-198.050 kJ}\cdot\textbf{mol}^{\mathbf{-1}}\\\end{array}

ΔG is negative, so the reaction is spontaneous.

4 0
3 years ago
A mercury manometer is used to measure pressure in the container illustrated. Calculate the pressure exerted by the gas if atmos
Brilliant_brown [7]

Answer:

<em> Pressure exerted by the gas is 574.85 torr</em>

Explanation:

Atmospheric pressure = 751 torr

but 1 torr = 1 mmHg

therefore,

atmospheric pressure = 751 mmHg

1 mmHg = 133.3 Pa

therefore,

atmospheric pressure = 751 x 133.3 = 100108.3 Pa

distance labeled (tube section with mercury) = 176 mm

the pressure within the tube will be

P_{tube} = ρgh

where ρ is the density of mercury = 13600 kg/m^3

h is the labeled distance = 176 mm = 0.176 m

g is acceleration due to gravity = 9.81 m/s^2

P_{tube}  = 13600 x 9.81 x 0.176 = 23481.216 Pa

The general equation for the pressure in the manometer will be

P_{atm} = P_{tube} + P_{gas}

where P_{atm}  is the atmospheric pressure

P_{tube}  is the pressure within the tube with mercury

P_{gas} is the pressure of the gas

substituting, we have

100108.3 = 23481.216 + P_{gas}

P_{gas} = 100108.3 - 23481.216 = <em>76627.1 Pa</em>

This pressure can be stated in mmHg as

76627.1 /133.3 =<em> 574.85 mmHg </em>

and also equal to<em> 574.85 torr</em>

6 0
3 years ago
Transition elements
Bond [772]
I believe the answer is E.
7 0
3 years ago
Read 2 more answers
A fusion reaction takes place between carbon and another element. Neutrons are released, and a different element is formed. The
sdas [7]

Answer:

Dependent on the element that reacted with carbon

Explanation:

Nuclear fusion is the combination of small atomic nuclei into larger ones usually accompanied with the release of a large amount of energy.

From the problem stated, carbon fuses with another atom. The combined atom would have more nuclear particles in terms of protons and neutrons than the combining atoms. This will eventually make it weigh more than carbon and the atom it combines with. The resulting weight will depend on the combining atoms eventually.

7 0
3 years ago
Read 2 more answers
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