Answer:
αβ = Ma
Explanation:
By Newton's 2nd Law, the equation governing the motion of the rocket while the rocket is burning fuel is
αβ = Ma where α = rocket's fuel burning rate, β = relative to the velocity of the rocket, M = instantaneous mass of the rocket and a = acceleration of rocket.
Weight of the child m = 50 kg
Radius of the merry -go-around r = 1.50 m
Angular speed w = 3.00 rad/s
(a)Child's centripetal acceleration will be a = w^2 x r = 3^2 x 1.50 => a = 9 x
1.5
Centripetal Acceleration a = 13.5m/sec^2
(b)The minimum force between her feet and the floor in circular path
Circular Path length C = 2 x 3.14 x 1.50 => c = 3 x 3.14 => C = 9.424
Time taken t = 2 x 3.14 / w => t = 6.28 / 3 => t = 2.09
Calculating velocity v = distance / time = 9.424 / 2.09 m/s => v = 4.5 m/s
Calculating force, from equation F x r = mv^2 => F = mv^2 / r => 50 x (4.5)^2
/ 1.5
F = 50 x 3 x 4.5 => F = 150 x 4.5 => F = 675 N
(c)Minimum coefficient of static friction u
F = u x m x g => u = F / m x g => u = 675/ 50 x 9.81 => 1.376
u = 1.376
Hence with the force and the friction coefficient she is likely to stay on merry-go-around.
Explanation:
Mechanical Advantage (MA)
MA=d1d2=FoutFin ; d1 is the distance of effort, d2 is the distance the object is moved
The <span>stream's discharge
The volume of water to pass a given point on a stream bank per unit of time, usually expressed in cubic meters of water per second. </span>
Answer:20/47 meter per second
Explanation:
Mass of arrow(ma)=0.25kg
Velocity of arrow(va)=12m/s
Mass of target(mt)=6.8kg
Velocity of target(vt)=0 since target is at rest
Conservation of linear momentum says that :
maxva+mtxvt=(ma+mt)V
V=(maxva+mtxvt)/(ma+mt)
V=(0.25x12+6.8x0)/(0.25+6.8)
V=3/(7.05)
V=20/47 meter per second
