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inysia [295]
3 years ago
5

What is the equation of the line that is perpendicular to y= -4x +5 and passes through the point (4,-3)?

Physics
1 answer:
Ostrovityanka [42]3 years ago
5 0
Y=4x-19

Perpendicular because it has an opposite reciprocal slope
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Two long, straight wires are separated by 0.12 m. The wires carry currents of 4.0 A in opposite directions, as the drawing indic
user100 [1]
If we have I= 7.5 A:

I think my solution might just help you answer the problem on your own:

You have the formulas correct, watch your signs and BRACKETS. 

B = μ0/(2π) (Current) / (Perpendicular distance) 
Since μ0=4π E -7 Tm/A, we have: 
B1 = (4πE-7 Tm/A)(7.5 A)/[2π (0.030 m)] = 5E-5 T 
B2 = (4πE-7 Tm/A)(-7.5 A)/[2π (0.150 m)] = -1E-1 T 
So BA = B1 + B2 = ? 
(It looks like you just left out the square brackets, hence multiplying Pi and 0.03 and 0.15 instead of dividing them.) 

<span>For the point B, the two distances are -0.060 m and +0.060 m. Be careful with the signs. Unlike point A, the two components will have the same sign.</span>
3 0
3 years ago
Read 2 more answers
Scientists have changed the model of the atom as they have gathered new evidence. One of the atomic models is shown below.
yawa3891 [41]

Answer:

B: The colors of light emitted from heated atoms had very specific energies.

Explanation:

In Thompson's model of an atom the atom is said to be constituted of electrons which are surrounded by a haze of positive charge in order to balance the electrons' negative charges. It is also called plum prodding model because of negatively charged plums which are surrounded by the positively charged pudding.

Now, as the electrons move from higher to lower energy levels a photon which is a particle of light will be given off.

Thus, the correct answer is option B

7 0
4 years ago
7. A toy car of mass 1.2 kg is driving vertical circles inside a hollow cylinder of radius 2.0m. It is moving at a constant spee
wlad13 [49]

Answer:

a)

N_{top}=9.8N\\N_{bottom}=33.4N

b) v_{min}=4.4m/s

Explanation:

The net force on the car must produce the centripetal acceleration necessary to make this circle, which is a_{cp}=\frac{v^2}{R}. At the top of the circle, the normal force and the weight point downwards (like the centripetal force should), while at the bottom the normal force points upwards (like the centripetal force should) and the weight downwards, so we have (taking the upwards direction as positive):

-m\frac{v^2}{R}=-N_{top}-mg\\m\frac{v^2}{R}=N_{bottom}-mg

Which means:

N_{top}=m\frac{v^2}{R}-mg=(1.2kg)\frac{(6m/s)^2}{2m}-(1.2kg)(9.8m/s^2)=9.8N\\N_{bottom}=m\frac{v^2}{R}+mg=(1.2kg)\frac{(6m/s)^2}{2m}+(1.2kg)(9.8m/s^2)=33.4N

The limit for falling off would be N_{top}=0, so the minimum speed would be:

0=m\frac{v_{min}^2}{R}-mg\\v_{min}=\sqrt{Rg}=\sqrt{(2m)(9.8m/s^2)}=4.4m/s

3 0
3 years ago
A 6.00 μFμF capacitor that is initially uncharged is connected in series with a 4.00 ΩΩ resistor and an emf source with EE EMF =
Sindrei [870]

Answer: Rr = 900w

T = 1.66×10^-5s

P = 36.92W

Explanation: please find the attached file for the solution.

3 0
3 years ago
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How far does a ca4 go
miv72 [106K]

Answer:

as far as the car can withstand

Explanation:

5 0
3 years ago
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