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r-ruslan [8.4K]
3 years ago
10

If the plotted points on a speed-time graph do not form a straight line, what do you know about the object's acceleration?

Physics
2 answers:
slega [8]3 years ago
6 0
Remember, that while sped is constant, acceleration is not. Acceleration is when velicity changes. So the graph which shows the slop <span>of a velocity vs time describes acceleration.
</span>If we have the straight line on the graph it means that the slope is always the same whereas the <span>non-linear graphs has a variable slope that changes depending on your point in the graph.
</span>To conclude - if your graph is not a straight line it has variable acc at many points.<span>

</span>
Morgarella [4.7K]3 years ago
3 0

I accidentally answered the wrong one. Im sorry (edit)

Explanation:

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A wheel has a constant angular acceleration of 1.9 rad/s2. During a certain 7.0 s interval, it turns through an angle of 63 rad.
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Explanation:

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3 years ago
Which word means "to get away from something"? <br> a become b dream c escape d practice
klemol [59]

The correct answer is - c. escape.

The word ''escape'' means to get away from something. This word can be used for multiple different situations, and it can refer to both physical and psychological matters.

In a physical sense it can be used to escape from certain unpleasant, or dangerous situation. Example: I have to escape from this prison.

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5 0
3 years ago
Arigid body must rotate about an axis in order for it to have angular momentum about that axis. True False
kompoz [17]

Answer:

False

Explanation:

Let's consider the definition of the angular momentum,

\vec{L} = I \vec{\omega}

where I = \int\limits_m r^2 dm = \lim_{n \to \infty} \sum\limits_{i=1}^n m_i r_i^2 is the moment of inertia for a rigid body. Now, this moment of inertia could change if we change the axis of rotation, because "r" is defined as the distance between the puntual mass and the nearest point on the axis of rotation, but still it's going to have some value. On the other hand,

\vec{\omega} = \frac{\vec{r} \times \vec{v}}{r^2} so \vec{\omega} \neq 0 unless \vec{r} ║  \vec{v}.

In conclusion, a rigid body could rotate about certain axis, generating an angular momentum, but if you choose another axis, there could be some parts of the rigid body rotating around the new axis, especially if there is a projection of the old axis in the new one.

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Answer:

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