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Sever21 [200]
3 years ago
5

Cl2 is a stable diatomic molecule. It can be decomposed to form two Cl atoms as

Chemistry
1 answer:
Nikitich [7]3 years ago
4 0

Answer:

Option B: ΔH is (+); endothermic

Explanation:

From the reaction Cl2 → 2Cl(g) given, we can see that the number of moles on the left hand side is 1 while on right hand side, it is 2. This means the number of moles are increasing and it means that the randomness of the system has increased. Also, the bonds are being broken down.

Therefore, the reaction is endothermic. In endothermic reactions, ΔH is positive.

Thus, the correct option is option B.

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What do u notice about the molecules before and after the chemical reaction
dimaraw [331]

Explanation:

In a chemical reaction, the atoms and molecules produced by the reaction are called products.

In a chemical reaction, only the atoms present in the reactants can end up in the products. No new atoms are created, and no atoms are destroyed.

In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

6 0
3 years ago
Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.
Misha Larkins [42]
Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

 moles HCl = moles KOH \\  \\ cHCl*vHCl=cKOH*vKOH \\  \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}=  541,54mL

So, the required volume of HCl is 541,54 mL

Have a nice day!
8 0
3 years ago
How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?
max2010maxim [7]

Answer: A volume of 600 mL of 3.0 M H_{2}SO_{4} solution can be prepared by using 100.0 mL OF 18 M H_{2}SO_{4}.

Explanation:

Given: V_{1} = ?,        M_{1} = 3.0 M\\

V_{2} = 100.0 mL,       M_{2} = 18 M

Formula used to calculate the volume is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\3.0 M \times V_{1} = 18 M \times 100.0 mL\\V_{1} = \frac{18 M \times 100.0 mL}{3.0M}\\= 600 mL

Thus, we can conclude that a volume of 600 mL of 3.0 M H_{2}SO_{4} solution can be prepared by using 100.0 mL OF 18 M H_{2}SO_{4}.

6 0
3 years ago
If the temperature of the earth's layers increases by about 90 degrees fahrenheit for every 1 mile from the surface and you are
bogdanovich [222]
The rate of change of the temperature of the Earth's surface is given to,
                                       90°F/mile
To determine the temperature x miles away from the surface, we multiply the depth by the given rate. This will give us the answer of,
                                  T = (90°F/mile)(90 mile)
                                      = 8100°F
Thus, the temperature 90 miles deep in the Earth's surface is equal to 8100°F. 
4 0
3 years ago
Read 2 more answers
Why ph changes disrupt protein's ionic bonds?
Inessa05 [86]

Answer:

A change in pH in the protein habitat can modify its ionic bonds because because the chemical equilibrium shifts to one side or the other depends on the modification

Explanation:

The pH influences the charge acquired by the acidic and basic groups present in the molecules. Proteins usually have groups with characteristics of acid or weak base. Therefore, they are partially ionized in solution coexisting in equilibrium different species.

The degree of ionization of the different functional groups is in relation to the pH of the medium in which they are found, since the H3O + and OH- species are part of the equilibrium situation. Therefore, according to the pH, each group with characteristics of weak acid or base present in the molecule will be ionized to a lesser or greater extent. There are extreme situations where the balance has been totally displaced in one direction, for example: under very high pH conditions (low concentration of H3O +) weak acids are considered fully ionized, so the functional group will always have an electric charge. The same goes for the bases at very low pH values. In other equilibrium situations, species of the same molecule with different load will coexist in the solution, due to the pH value of the medium in which it is found.

8 0
3 years ago
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