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allochka39001 [22]

2 years ago

14

Once a rate law is determined from trials with concentration and rate data, what is the minimum number of additional trials that

will have to be done to gather sufficient initial rates data to be able to find the rate constant for the reaction? a. 0b. 1c. 2d. 3

1 answer:

Otrada [13]2 years ago

8 0

Answer:

A is probably ur answer

Explanation:

but if I'm wrong My bad and at least I tried

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The mass of an iron(II) sulfate crystal is 8.36 g.How many moles of FeSO4 are in the crystal?

Yuki888 [10]

The number of moles present in the FeSO4 are 0.055 mol.

<u>Explanation:</u>

The mass of a substance containing the same number atoms in 12.0 g of 12C is known as mole. One mole of any substance is equal to 6.023 x 10^23. The moles of a substance can be determined by using the formula,

Number of moles = mass in grams / molecular mass

Given,

mass = 8.36 g,

molecular mass of FeSO4 = 151.908 g / mol

number of moles = 8.36 / 151.908

= 0.055 mol.

5 0

3 years ago

The thin outer layer of Earth, called the crust, contains only 0.50 percent of Earth's total mass and yet is the source of almos

Rzqust [24]

Answer:

The mass of silicon in kilograms in Earth's crust is $7.2729\times 10^{21} kg$ .

Explanation:

Mass of Earth = $5.9\times 10^{21} tons$

(1 ton= 2000 lb)

(1 lb =453.6 g)

1 ton = 2000 × 453.6 g =907,200 g

Mass of Earth = $5.9\times 10^{21}\times 907,200 g=5.3524\times 10^{27} g$

Percentage of earth crust = 0.50%

Mass of earth crust = M

$0.50\%=\frac{M}{5.3524\times 10^{27}}\times 100$

$M=2.6762\times 10^{25} g$

Percentage of the silicon in Earth's crust = 27.2 %

Mass of silicon in in Earth's crust = m

$Si\%=\frac{m}{M}\times 100$

$27.2\%=\frac{m}{2.6762\times 10^{25} g}\times 100$

$m = 7.2792\times 10^{24} g=7.2729\times 10^{21} kg$

1000 g = 1 kg

The mass of silicon in kilograms in Earth's crust is $7.2729\times 10^{21} kg$ .

7 0

3 years ago

What do scientists call organisms, such as plants, which make their own food?

larisa [96]

Most plants are called autotrophs they make their own food

5 0

3 years ago

Calculate the number of calories needed to increase the temperature of 50.0 g of copper metal from 21.0 degrees C to 75.0 degree

KonstantinChe [14]

<h3>Answer:</h3>

1031.4 Calories.

<h3>Explanation:</h3>

We are given;

Mass of the copper metal = 50.0 g

Initial temperature = 21.0 °C

Final temperature, = 75°C

Change in temperature = 54°C

Specific heat capacity of copper = 0.382 Cal/g°C

We are required to calculate the amount of heat in calories required to raise the temperature of the copper metal;

Quantity of heat is given by the formula,

Q = Mass × specific heat capacity × change in temperature

= 50.0 g × 0.382 Cal/g°C × 54 °C

= 1031.4 Calories

Thus, the amount of heat energy required is 1031.4 Calories.

4 0

3 years ago

2 NaCL + CaO = CaCL2 + Na2O

Naily [24]

222 grams of calcium chloride is produced.

<h3><u>Explanation</u>:</h3>

The mole concept and the chemical equation are very much closely related with each other. In the chemical reaction, the compounds or elements in both sides are balanced according to the number of atoms of each side of the reaction. So from there we can easily find the amount of reactant reacts to produce desired product.

Here we can see that 2 moles of sodium chloride produces 1 mole of calcium chloride.

So, 4 moles of sodium chloride will produce 2 moles of calcium chloride.

Now, atomic weight of calcium =40.

Atomic weight of chlorine =35.5.

So,the molecular weight of calcium chloride = $40+ 35.5\times2$

=111.

It means, 1 mole of calcium chloride weighs 111 grams.

So 2 moles of calcium chloride weighs $111\times2$ grams = 222 grams.

7 0

3 years ago