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Shtirlitz [24]
3 years ago
13

A point on the end of a tuning fork moves in simple harmonic motion described by d = a sin ωt. Find ω given that the tuning fork

for a certain note has a frequency of 256 vibrations per second.
Physics
1 answer:
pantera1 [17]3 years ago
5 0

Answer:

1609.1429 rad/sec

Explanation:

By using the relation Angular velocity and frequency as:

Angular velocity (ω) = 2×π×Frequency (ν)

Given the frequency = 256 vibrations per second.

So, Angular velocity can be calculated by using the above formula as:

Angular velocity (ω) = 2×π×Frequency (ν)

⇒Angular velocity (ω) = 2×π×256 rad/ sec

⇒Angular velocity (ω) = 2×(22/7)×256 rad/ sec

<u>⇒Angular velocity (ω) = 1609.1429 rad/ sec</u>

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emmasim [6.3K]

Assume <em>R</em> is measured in meters (m) and <em>M</em> in kilograms (kg). Then

<em>R</em> ² / (<em>GM</em>) = [m]² / ([N•m²/kg²] [kg]) = m•kg / N = m•kg / (kg•m/s²) = s²

so <em>t</em> ² is indeed proportional to <em>R</em> ²/(<em>GM</em>).

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A marathon runner completes a 42.238 km course in 2 h, 31 min, and 46 s . There is an uncertainty of 29 m in the distance run an
icang [17]

Answer:

The percentage uncertainty in the average speed is 0.10% (2 sig. fig.)

Explanation:

Consider the formula for average speed \bar{v}.

\displaystyle \bar{v} = \frac{s}{t},

where

  • s is the total distance, and
  • t is the time taken.

The percentage uncertainty of a fraction is the sum of percentage uncertainties in

  • the numerator, and
  • the denominator.

What are the percentage uncertainties in s and t in this question?

The unit of the absolute uncertainty in s is meters. Thus, convert the unit of s to meters:

s = \rm 42.238\;km = 42.238\times 10^{3}\;m.

\begin{aligned}\displaystyle \text{Percentage Uncertainty in }s &= \frac{\text{Absolute Uncertainty in } s}{\text{Measured Value of }s}\times 100\% \\ &=\rm\frac{29\; m}{42.238\times 10^{3}\;m}\times 100\%\\ &= 0.0687\%\end{aligned}.

The unit of the absolute uncertainty in t is seconds. Convert the unit of t to seconds:

t = \rm 2\times 3600 + 31\times 60 + 46 = 9106\;s

Similarly,

\begin{aligned}\displaystyle \rm \text{Percentage Uncertainty in }t &= \frac{\text{Absolute Uncertainty in }t}{\text{Measured Value of }t}\times 100\% \\ &=\rm\frac{46\; s}{9106\;s}\times 100\%\\ &= 0.0329\%\end{aligned}.

The average speed \bar{v} here is a fraction of s and t. Both s and t come with uncertainty. The percentage uncertainty in \bar{v} will be the sum of percentage uncertainties in s and t. That is:

\text{Percentage Uncertainty in }\bar{v}\\=(\text{Percentage Uncertainty in } s) + (\text{Percentage Uncertainty in } t)\\ = 0.0687\% + 0.0329\%\\ = 0.010\%.

Generally, keep

  • two significant figures for percentage uncertainties that are less than 2%, and
  • one for those that are greater than 2%.

The percentage uncertainty in \bar{v} here is less than 2%. Thus, keep two significant figures. However, keep more significant figures than that in calculations to make sure that the final result is accurate.

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4 years ago
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