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Shtirlitz [24]
3 years ago
13

A point on the end of a tuning fork moves in simple harmonic motion described by d = a sin ωt. Find ω given that the tuning fork

for a certain note has a frequency of 256 vibrations per second.
Physics
1 answer:
pantera1 [17]3 years ago
5 0

Answer:

1609.1429 rad/sec

Explanation:

By using the relation Angular velocity and frequency as:

Angular velocity (ω) = 2×π×Frequency (ν)

Given the frequency = 256 vibrations per second.

So, Angular velocity can be calculated by using the above formula as:

Angular velocity (ω) = 2×π×Frequency (ν)

⇒Angular velocity (ω) = 2×π×256 rad/ sec

⇒Angular velocity (ω) = 2×(22/7)×256 rad/ sec

<u>⇒Angular velocity (ω) = 1609.1429 rad/ sec</u>

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A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90 s. You may ignore air
Gekata [30.6K]

Answer: Height of building = 17.69m, velocity of brick = 18.6m/s

Explanation: From the question, the body has a zero initial speed, thus initial velocity (u) all through the motion is zero.

By ignoring air resistance makes it a free fall motion thus making it to accelerate constantly with a value of a = 9.8m/s^{2}.

Time taken to fall = 1.90s

a)

thus the height of the building is calculated using the formulae below

H = ut + \frac{1}{2} gt^{2}

but u = 0 , hence

H = \frac{1}{2} gt^{2}

H = \frac{1}{2} *9.8* 1.9^{2} \\\\H = 17.69m

b)

to get the value of velocity (v) as the brick hits the ground, we use the formulae below

v^{2} = u^{2} + 2aH

but u= 0, hence

v^{2} = 2gH\\

v^{2} = 2 * 9.8 * 17.69\\v = \sqrt{2 *9.8* 17.69} \\v = 18.62m/s

 

find the attachment in this answer for the accleration- time graph, velocity- time graph and distance time graph

8 0
4 years ago
A message encoded by changing the voltage of an electric current is called __________.
VMariaS [17]

Answer:

It is called an electronic signal.

6 0
3 years ago
Read 2 more answers
What is the bump on the lateral side just proximal to the 5th metatarsal?
xeze [42]
The description refers to the styloid process or tuberosity. This styloid process is seen in the 5th metatarsal and this area shows the fifth metatarsal's growth plate. This bone is being attached by strong tendon known as the <span>Peroneus brevis tendon.</span>
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4 years ago
A particular form of electromagnetic radiation has a frequency of 5.42x10^15 Hz. What is the wavelength is nanometers? meters?
zubka84 [21]
Electromagnetic radiation are represented in waves. Each type of wave has a certain shape and length. The distance between two peaks in a wave is called the wavelength. This value is equal to the speed of light divided by the frequency.
Wavelength = c/f
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</span><span>Wavelength = 5.54 x 10^-8 m = 55.35 nm</span>
4 0
3 years ago
If a nucleus was as big as a nonpareil, an atom would be ____
Mamont248 [21]

Answer:

small marble  

Explanation:

A nonpareil are confectionery tiny ball items that are made up of starch and sugar. It is very small of the size of sugar crystal or sand grains. They were the miniature version of the comfits. They are generally opaque white but bow available in all colors.

In the context, if the nucleus is compared to the size of a nonpareil then its atom would be of the size of small size marble. An atom is bigger in size than that of nucleus as the nucleus is located inside the atoms.

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