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Savatey [412]
2 years ago
12

When the rubber sheet is pulled down, the volume of the bell jar is ____________ and the pressure in the bell jar is ___________

_, which causes air to flow the balloons. This scenario represents the process of ____________.
Physics
1 answer:
Makovka662 [10]2 years ago
8 0

Answer:

increases, decreases, respiration

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An astronaut having mass 320 kg with equipment included is attempting an untethered space walk. The astronaut is initially at re
ExtremeBDS [4]
This can be solved using momentum balance, since momentum is conserved, the momentum at point 1 is equal to the momentum of point 2. momentum = mass x velocity
m1v1 = m2v2
(0.03kg x 900 m/s ) = 320(v2)
v2 = 27 / 320
v2 = 0.084 m/s is the speed of the astronaut
7 0
3 years ago
An 7.5 × binocular has 3.7-cm-focal-length eyepieces. What is the focal length of the objective lenses? Express your answer to t
elixir [45]

To solve this problem we will apply the concept of magnification, which is given as the relationship between the focal length of the eyepieces and the focal length of the objective. This relationship can be expressed mathematically as,

\mu = \frac{f_0}{f_e}

Here,

\mu = Magnification

f_e = Focal length eyepieces

f_0 = Focal length of the Objective

Rearranging to find the focal length of the objective

f_0 = \mu f_e

Replacing with our values

f_0 = 7.5* 3.7cm

f_0 = 27.75cm

Therefore the focal length of th eobjective lenses is 27.75cm

5 0
3 years ago
What is the net force of a 25 g object with an acceleration of 3 m/s^2? 100PTS
gayaneshka [121]

Explanation:

Force=Mass×acceleration

force=25×3

force=75N

5 0
3 years ago
Read 2 more answers
An object moves in one dimensional motion with constant acceleration a = 4.2 m/s^2. At time t = 0 s, the object is at x0 = 3.9 m
solong [7]

Answer:

The object will move to Xfinal = 7.5m

Explanation:

By relating the final velocity of the object and its acceleration, I can obtain the time required to reach this velocity point:

Vf= a × t ⇒ t= (7.2 m/s) / (4.2( m/s^2)) = 1,7143 s

With the equation of the total space traveled and the previously determined time I can obtain the end point of the object on the x-axis:

Xfinal= X0 + /1/2) × a × (t^2) = 3.9m + (1/2) × 4.2( m/s^2) × ((1,7143 s) ^2) =

= 3.9m + 3.6m = 7.5m

8 0
3 years ago
How to do this question plz answer ​
Monica [59]

Answer:

I can't see the attachment it's too blury I can see bout two words and thats it

Explanation:

Think i got an eye infection or bad eye sight

3 0
2 years ago
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