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prisoha [69]
3 years ago
14

A student has a solution of sodium nitrate and believes it is saturated. Which statement provides the best evidence that the sol

ution is saturated? A. When more water is added, the appearance of the solution doesn’t change. B. When some of the water evaporates, all of the sodium nitrate remains dissolved. C. When a small amount of sodium nitrate is added, a large amount precipitates from the solution. D. When additional sodium nitrate is added, it all settles to the bottom of the container. E. When the temperature of the solution is increased, additional sodium nitrate can be dissolved.
Chemistry
1 answer:
Vsevolod [243]3 years ago
4 0

Answer : The correct option is, D

Explanation :

Saturated solution : It is a chemical solution which contain the maximum amount of solute dissolved in the solvent. In saturated solution, the additional amount of solute will not dissolve in the solvent.

When a student has a solution of sodium nitrate then we can check their saturation point by adding additional amount of sodium nitrate. When we add more amount of sodium nitrate in the solution, then all of it will settle down to the bottom of the container.

Therefore, the best evidence for saturated solution is, When additional sodium nitrate is added, it all settles to the bottom of the container.

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Answer:

0.00500M of Na₂C₂O₄

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<em>When are dissolved in 150 mL of 1.0 M H2SO4.</em>

<em />

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3 years ago
A) The average molecular speed in a sample of Ar gas at a certain temperature is 391 m/s. The average molecular speed in a sampl
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<u>Answer:</u>

<u>For A:</u> The average molecular speed of Ne gas is 553 m/s at the same temperature.

<u>For B:</u> The rate of effusion of SO_2 gas is 1.006\times 10^{-3}mol/hr

<u>Explanation:</u>

<u>For A:</u>

The average molecular speed of the gas is calculated by using the formula:

V_{gas}=\sqrt{\frac{8RT}{\pi M}}

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V_{gas}\propto \sqrt{\frac{1}{M}}

where, M is the molar mass of gas

Forming an equation for the two gases:

\frac{V_{Ar}}{V_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{Ar}}}          .....(1)

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V_{Ar}=391m/s\\M_{Ar}=40g/mol\\M_{Ne}=20g/mol

Plugging values in equation 1:

\frac{391m/s}{V_{Ne}}=\sqrt{\frac{20}{40}}\\\\V_{Ne}=391\times \sqrt{2}=553m/s

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<u>For B:</u>

Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation for this follows:

Rate\propto \frac{1}{\sqrt{M}}

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Forming an equation for the two gases:

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