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almond37 [142]
3 years ago
9

What is the ratio of phosphorous atoms to oxygen atoms

Chemistry
1 answer:
ozzi3 years ago
6 0
2:5 is the answer have a awesome day
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How do you draw acetone using a Bohr model?
Inessa [10]

Explanation:

this is the one i found.....

6 0
2 years ago
In a solution, the substance that changes phase is the _____, while the substance that does not change phase is the____.
iren [92.7K]
Phase change is the solute
the one that doesn't phase change is the solvent.
A
6 0
3 years ago
Read 2 more answers
What is the molecule shown below?
FrozenT [24]

Answer:

2,3–dimethylpentane

Explanation:

To know which option is correct, we shall determine the name of the compound.

To obtain the name of the compound, do the following:

1. Determine the longest continuous carbon chain. This gives the parent name of the compound.

2. Identify the substituent group attached to the compound.

3. Locate the position of the substituent group by giving it the lowest possible count.

4. Combine the above to obtain the name of the compound.

Now, we shall determine the name of the compound as follow:

1. The longest continuous carbon chain is 5. Thus, the parent name of the compound is pentane.

2. The substituent group attached is methyl (–CH₃)

3. There are two methyl group attached to the compound. One is located at carbon 2 and the other at carbon 3.

4. Therefore, the name of the compound is:

2,3–dimethylpentane

None of the options are correct.

8 0
2 years ago
Calculate the percent by volume of a solution that has 75 mL of solute dissolved in 375 mL of solution. Show your work and round
Mandarinka [93]

Answer:

The answer is 20 % V/V

Explanation:

We use this formula for calculate the %V/V:

%V/V= (ml solute/ml solution) x 100= (75ml/375 ml)x 100 = 20 % V/V

<em>The% V / V represents the amount of ml of solute dissolved in 100 ml of solution</em>

7 0
3 years ago
draw the organic product formed when 1−hexyne is treated with h2o, h2so4, and hgso4. click the draw structure button to launch t
V125BC [204]

The organic product formed when 1−hexyne is treated with H₂O, H₂SO₄, and HgSO₄ will be 2-hexanone (structure attached).

This reaction is an example of an oxymercuration reaction of the organic product 1−hexyne.

Oxymercuration is shown in three steps to the right. The nucleophilic double bond attacks the mercury ion, releasing an acetoxy group. The mercury ion's electron pair attacks carbon on the double bond, generating a positive-charged mercuronium ion. Mercury's dxz and 6s orbitals give electrons to the double bond's lowest unoccupied molecular orbitals.

In the second stage, the nucleophilic H₂O attacks the highly modified carbon, freeing its mercury-bonding electrons. Electrons neutralize mercury ions by collapsing. Water molecules have positive-charged oxygen.

In the third stage, the negatively charged acetoxy ion released in the first step attacks the hydrogen of the water group, generating the waste product HOAc. The two electrons in the oxygen-hydrogen link collapse into oxygen, neutralizing its charge and forming alcohol.

You can also learn about organic products from the following question:

brainly.com/question/13513481

#SPJ4

4 0
1 year ago
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