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umka2103 [35]
3 years ago
14

How does the genetic makeup of the skin cells differ from the genetic makeup of the gametes?

Physics
2 answers:
QveST [7]3 years ago
6 0

Answer:

Gametes contain half the number of chromosomes. - Skin cells of an individual are normally genetically identical and gametes have variation. - Skin cells = 2n/46/diploid; gametes = n/23/haploid. - Skin cells have twice as much genetic material.

Explanation:

exis [7]3 years ago
3 0

Answer:

Gametes contain half the number of chromosomes. -Skin cells have twice as much genetic material.

Explanation:

Hope this helps!!

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In what climates would you expect soil to form fastest? Why?
enyata [817]

Answer:

Soils develop faster in warm, moist climates and slowest in cold or arid ones. Rainfall is one of the most important climate factors in soil formation.

Please mark me brainliest!

Hope this helped God bless :)

5 0
3 years ago
A satellite m-500 kg orbits the earth at a distance d 215 km, above the surface of the planet. The radius of the earth is re 6.3
AnnZ [28]

Answer:

7.78 * 10³ m/s

Explanation:

Orbital velocity is given as:

v = √(GM/R)

G = 6.67 * 10^(-11) Nm/kg²

M = 5.98 * 10^(24) kg

R = radius of earth + distance of the satellite from the surface of the earth

R = 2.15 * 10^(5) + 6.38 * 10^(6)

R = 6.595 * 10^(6) m

v = √([6.67 * 10^(-11) * 5.98 * 10^(24)] / 6.595 * 10^(6))

v = √(6.048 * 10^7)

v = 7.78 * 10³ m/s

4 0
3 years ago
The Astronomer Carl Sagan is famous. Why?
Zolol [24]
Mainly because he was Johnny Carson's advisor and consultant
on space, astronomy, and science in general, and he appeared
on The Tonight Show Starring Johnny Carson many times.
6 0
3 years ago
A 70 kg base runner begins his slide into second base while moving at a speed of 4.35 m/s. He slides so that his speed is zero j
sladkih [1.3K]

Answer

given,

Mass of the runner, M = 70 Kg

speed of the runner on the second base = 4.35 m/s

speed at the base = 0 m/s

Acceleration due to gravity,g = 9.8 m/s²

a) magnitude of mechanical energy lost

  Mechanical energy lost is equal top gain in kinetic energy

   ME_{Lost}=\dfrac{1}{2}mv^2

   ME_{Lost}=\dfrac{1}{2}\times 70\times 4.35^2

   ME_{Lost}=662.29\ J

b) Work done = Force x displacement

    W = F. x

     F = μ mg

    W = μ mg . x

Work done is equal to 662.29 J

  x=\dfrac{W}{\mu m g}

using the coefficient of the friction,μ = 0.7

  x=\dfrac{662.29}{ 0.7\times 70\times 9.8}

     x = 1.38 m

Hence, the runner will slide to 1.38 m.

3 0
3 years ago
ASK YOUR TEACHER A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 51.5-gram mass is attach
Simora [160]

Answer:

0.114 kg or 114 g

Explanation:

From the diagram attaches,

Taking the moment about the fulcrum,

sum of clockwise moment = sum of anticlockwise moment.

Wd = W'd'

Where W = weight of the mass, W' = weight of the meter rule, d = distance of the mass from the fulcrum, d' = distance of the meter rule.

make W'  the subject of the equation

W' = Wd/d'................ Equation 1

Given: W = mg = 0.0515(9.8) = 0.5047 N, d = (39.2-16) = 23.2 cm, d' = (49.7-39.2) = 10.5 cm

Substitute these values into equation 1

W' = 0.5047(23.2)/10.5

W' = 1.115 N.

But,

m' = W'/g

m' = 1.115/9.8

m' = 0.114 kg

m' = 114 g

6 0
3 years ago
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