All categories

3 years ago

Exit what occurs when a wave causes vibration in a nearby object that matches the frequency of the wave?

1 answer:

7 0

<span>when a wave causes vibration in a nearby object that matches the frequency of the wave, the phenomenon that occurs is called resonance.
It produces a sound of larger amplitude as a result of vigorous vibration of the body.
</span>

You might be interested in

Which of the following organs are found in the

Hatshy [7]

Answer:

small intestine, tongue and large intestine

Explanation:

The GI tract is a series of hollow organs joined in a long, twisting tube from the mouth to the anus. The hollow organs that make up the GI tract are the mouth, esophagus, stomach, small intestine, large intestine, and anus. The liver, pancreas, and gallbladder are the solid organs of the digestive system.

3 0

3 years ago

When testing a laptop power connector, how close should the voltage measured be to the accepted voltage of the laptop?

elixir [45]

When testing a laptop power connector, the voltage measured has be close to +/- 5% to the accepted voltage of the laptop. This is to ensure that the power connector would not pose any hazard to the user and is safe for use. So, for instance the accepted voltage is 19 V, when you test the power connector it should be that the reading is between 18 V to 20 V. Any reading below or above that range is not recommended for use. You can locate the accepted voltage on the battery or the laptop itself. To test a power connector, you can use a volt meter or a multi meter.

4 0

4 years ago

To practice tactics box 5.2 working with objects in contact. a 1200-kg car pushes a 2100-kg truck that has a dead battery to the

Reptile [31]

Mass of the car = 1200 kg

Mass of the truck = 2100 kg

Total mass of car and truck = 2100 + 1200 = 3300 kg

Since, the car pushes the truck. Hence, they will move together and will have same acceleration.

Let the acceleration be a.

According to Newton's second law:

F(net) = ma

F = 4500 N

4500 = 3300 × a

$a = \frac{4500}{3300}$

a = 1.36 m/s^2

Let the force applied by the car on truck be F.

F = F(net) on the truck

F = ma

F = 2100 × 1.36

F = 2856 N

Hence, the force applied by the car on the truck is 2856 N

6 0

3 years ago

Read 2 more answers

A certain atom has atomic number Z = 25 and atomic mass number A = 52. a. What is the approximate radius of the nucleus of this

wlad13 [49]

Answer:

a)The approximate radius of the nucleus of this atom is 4.656 fermi.

b) The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

Explanation:

$r=r_o\times A^{\frac{1}{3}}$

$r_o=1.25 \times 10^{-15} m$ = Constant for all nuclei

r = Radius of the nucleus

A = Number of nucleons

a) Given atomic number of an element = 25

Atomic mass or nucleon number = 52

$r=1.25 \times 10^{-15} m\times (52)^{\frac{1}{3}}$

$r=4.6656\times 10^{-15} m=4.6656 fm$

The approximate radius of the nucleus of this atom is 4.656 fermi.

b) $F=k\times \frac{q_1q_2}{a^2}$

k= $9\times 10^9 N m^2/C^2$ = Coulombs constant

$q_1,q_2$ = charges kept at distance 'a' from each other

F = electrostatic force between charges

$q_1=+1.602\times 10^{-19} C$

$q_2=+1.602\times 10^{-19} C$

Force of repulsion between two protons on opposite sides of the diameter

$a=2\times r=2\times 4.6656\times 10^{-15} m=9.3312\times 10^{-15} m$

$F=9\times 10^9 N m^2/C^2\times \frac{(+1.602\times 10^{-19} C)\times (+1.602\times 10^{-19} C)}{(9.3312\times 10^{-15} m)^2}$

$F=2.6527 N$

The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

6 0

3 years ago

A slide whistle is an open-closed tube with an adjustable plunger that changes the length. You are playing the slide whistle and

Serjik [45]

Answer:

df / ft = -n 12 n= 1, 3, 5, ...

Explanation:

The speed of sound is

v = λ f

In a whistle that we approach by an open tube at one end and closed at the other, standing waves occur, which has a node in the closed part and a maximum in the open pate, whereby wavelength and the distance of the tube are related, the fundamental wave is

λ₁ = 4L

The harmonics are

λ₃ = 4L / 3

λ₅ = 4L / 5

The general formula

λₙ = 4L / n

with n = 1, 3, 5,…

We substitute and clear in the first equation

f = v n / 4L n = 1, 3, 5,…

Let's use derivatives to find the frequency change

df / dt = v n /4 dL⁻¹ / dt

d / dt (1/L) = - 1 / L² dL / dt

Where dL / dt = 8 cm / s

We replace

df / dt = - n v / L2 dL / dt

Let's calculate

df / dt = - n 340/152 8

df / ft = -n 12 n= 1, 3, 5, ...

4 0

4 years ago