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natali 33 [55]
3 years ago
15

What is the impulse of a 131g baseball when it strikes a batter at 57 m/s

Physics
1 answer:
lianna [129]3 years ago
8 0

Implulse=m(delta v)

Impulse=m(vf-vi)

Impulse=0.131(57)=7.467 (Js)

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If a transformer has 50 turns in the primary winding and 10 turns on the secondary winding, what is the reflected resistance in
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Explanation:

Given;

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number of turns in the secondary winding, N_S = 10 turns

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K = \frac{N_P}{N_S} \\\\K = \frac{50}{10} \\\\K = 5

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\frac{R_P}{R_S} = K^2\\\\R_P = R_SK^2\\\\R_P = 250(5)^2\\\\R_P = 6250 \ Ohms

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The 0.15kg baseball has a speed of v=30 m/s just before it is struck by the bat. It then travels along the trajectory shown befo
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The magnitude of the average impulsive force imparted to the ball if it is in contact with the bat is 6000 N

The mass of the baseball, m = 0.15 kg

The speed at which it moves, v = 30 m/s

Time at which the baseball was in contact with the bat, t = 0.75 ms

t = 0.75/1000 s

t  = 0.00075 s

The impulsive force is given by the formula:

F=\frac{mv}{t}

Substitute m = 0.15 kg, v = 30, and t = 0.00075s into the formula above:

F=\frac{0.15 \times 30}{0.00075} \\\\F=6000N

The magnitude of the average impulsive force imparted to the ball if it is in contact with the bat is 6000 N

Learn more here: brainly.com/question/25892144

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