Answer:
5
Explanation:
An atom has the same number of protons and electrons
Answer:
How the relative density of a substance is related to the density calculate the density of iron if its relative density is 2 and a density of water is 2gcm -3
R.d= relative density of substance/ relative density of water
R.d= 2/2
R.d= 1gcm-3
Explanation:
<span>Answer:
Hg2(NO3)2 + 2 NaCl --------> Hg2Cl2 + 2 NaNO3
Hg2+2 + 2NO3-1 + 2Na+ Cl- ----> Hg2Cl</span>
Some minerals tend to look alike.
Answer : The ratio of the protonated to the deprotonated form of the acid is, 100
Explanation : Given,

pH = 6.0
To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
Now put all the given values in this expression, we get:
![6.0=8.0+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=6.0%3D8.0%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
As per question, the ratio of the protonated to the deprotonated form of the acid will be:
Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100