<span><span><span>x3</span>+3x5</span>=x5</span><span>3x5+x3=x5</span>Subtract x^5 from both sides.<span>3x5+x3−<span>x5</span>=x5−<span>x5</span></span><span>2x5+x3=0</span>Factor left side of equation.<span><span><span>x3</span>(2x2+1)</span>=0</span>Set factors equal to 0.<span><span><span>x3</span>=0 or 2x2+1</span>=0</span><span>x=<span>0</span></span>
Answer:
109.6
Step-by-step explanation:
The question is not clear, but it is possible to obtain distance, s, from the given function. This, I would show.
Answer:
s = 17 units
Step-by-step explanation:
Given f(t) = t³ - 8t² + 27t
Differentiating f(t), we have
f'(t) = 3t² - 16 t + 27
At t = 0
f'(t) = 27
This is the required obtainaible distance, s.
Answer:
a = 4/27 - b/81
Step-by-step explanation:
27a + 1/3 * b = 4
Subtract the term with b from both sides.
27a = 4 - 1/3 *b
Divide both sides by 27.
a = 4/27 - 1/81 * b
a = 4/27 - b/81
Step-by-step explanation:
X-2y=5 ; 2x-4y=10
• x - 2y = 5 • 2x -4y = 10
-2y = -x+5 -4y= -2x +10
y1 = ½x - 5/2 y2 = ½x -5/2
• => y1 = y2
½x -5/2 = ½x -5/2
the systems have no solution
• graph as attached
