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3 years ago

Which of the following is the correct Lewis structure for ammonia ?

Chemistry

2 answers:

borishaifa [10]3 years ago

6 0

Is there any answer choices?

REY [17]3 years ago

4 0

Answer:

here are the answer choices

Explanation:

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Which stament about energy is mostly correct

klasskru [66]

I would say C is the most correct.
In D it depends on what water source you're using. Let's say it is a waterfall, then the source of the water (melting ice or a lake) may disappear in the future.
If you're using underwater "windmills" placed in the ocean, then you would expect it to last a while as the ocean will not disappear in the near future.

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3 years ago

In a desert, soil containing a mixture of sand and small rocks is exposed to wind erosion. Over time, how would the land surface

amid [387]

Sand dunes would be created due to the mixture falling on each other
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3 years ago

Read 2 more answers

0.32 g of a walnut is burned under an aluminum can filled with 58.1 mL of water. The water temperature in the can increases by 3

balu736 [363]

Answer:

1.8 × 10² cal

Explanation:

When 0.32 g of a walnut is burned, the heat released is absorbed by water and used to raise its temperature. We can calculate this heat (Q) using the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity of water

m: mass of water

ΔT: change in the temperature

Considering the density of water is 1 g/mL, 58.1 mL = 58.1 g.

Q = c × m × ΔT

Q = (1 cal/g.°C) × 58.1 g × 3.1°C

Q = 1.8 × 10² cal

3 0

3 years ago

A certain metal M crystallizes in a lattice described by a body-centered cubic (bcc) unit cell. The lattice constant (a, the edg

Furkat [3]

Answer:

radius = 156 pm

Explanation:

The relation between radius and edge length of unit cell of BCC is

r=a $\sqrt{3}$ /4

Given

a = 360 pm

Therefore

r = r = radius = 360 $\sqrt{3}$ /4= 155.88 pm

156 pm

3 0

3 years ago

Analysis of an athletes urine found the presence of a compound with a molar mass of 312 g/mol. How many moles of this compound a

rewona [7]

<h3>Answer:</h3>

= 5.79 × 10^19 molecules

<h3>Explanation:</h3>

The molar mass of the compound is 312 g/mol

Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)

We are required to calculate the number of molecules present

We will use the following steps;

<h3>Step 1: Calculate the number of moles of the compound </h3>

$Moles=\frac{mass}{molar mass}$

Therefore;

Moles of the compound will be;

$=\frac{0.030}{312g/mol}$

= 9.615 × 10⁻5 mole

<h3>Step 2: Calculate the number of molecules present </h3>

Using the Avogadro's constant, 6.022 × 10^23

1 mole of a compound contains 6.022 × 10^23 molecules

Therefore;

9.615 × 10⁻5 moles of the compound will have ;

= 9.615 × 10⁻5 moles × 6.022 × 10^23 molecules

= 5.79 × 10^19 molecules

Therefore the compound contains 5.79 × 10^19 molecules

5 0

3 years ago