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andre [41]
2 years ago
6

Balancing Chemical Equations

Chemistry
1 answer:
AURORKA [14]2 years ago
7 0

Answer:

Refer to the pictures.

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C because the animals was in danger
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What usally happens when two continentel plates converge
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select the common word on the outside of a shipping container that will alert you to the fact that the material inside is hazard
Paha777 [63]

The common word on the outside of a shipping container that will alert you to the fact that the material inside is hazardous is caution.

<h3>What are hazardous statements?</h3>

Hazardous statements are those words or phrases that are labelled against chemicals which shows the degree of how dangerous the chemical are.

The common words that are used as hazardous statements which shows that a chemical is dangerous include the following:

  • Danger,

  • Caution and

  • Warning.

Therefore, the common word on the outside of a shipping container that will alert you to the fact that the material inside is hazardous is caution.

Learn more about hazard statements here:

brainly.com/question/2875871

#SPJ1

3 0
2 years ago
Please help!
lakkis [162]

Answer:B

Explanation:

5 0
2 years ago
Refrigerant-134a enters the coils of the evaporator of a refrigeration system as a saturated liquid-vapor mixture at a pressure
Firdavs [7]

Answer:

(a) 0.699 kJ/K

(b) -0.671 kJ/K

(c) 0.028 kJ/K

Explanation:

The Refrigerant-134a flows into the evaporator as a saturated liquid-vapor mixture and flows out as a saturated vapor at a saturation pressure of 160 kPa and temperature of -15.64°C (estimated from the Saturated Refrigerant-134a Temperature Table).

(a) The entropy change of the refrigerant (ΔS_{R-134a}) = Q/T_{1}

Q = 180 kJ

T_{1} = -15.64 + 273.15 = 257.51 K

ΔS_{R-134a} = Q/T_{1} = 180/257.51 = 0.699 kJ/K

(b) The entropy change (ΔS_{c}) of the cooled space (ΔS_{c}) = -Q/T_{2}

Q = -180 kJ

T_{2} = -5 + 273.15 = 268.15 K

ΔS_{c} = Q/T_{2} = -180/268.15 = -0.671 kJ/K

(c) The total entropy change for this process (ΔS_{t}) = ΔS_{R-134a} + ΔS_{c} = 0.699 - 0.671 = 0.028 kJ/K

6 0
4 years ago
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