4 years ago

Traffic at a roundabout moves

Engineering

1 answer:

sweet-ann [11.9K]4 years ago

3 0

Answer:

b-counter-clockwise

Explanation:

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An automobile having a mass of 1100 kg initially moves along a level highway at 120 km/h relative to the highway. It then climbs

soldier1979 [14.2K]

Answer:

$-6111.11\ \text{kJ}$

$863.28\ \text{kJ}$

Explanation:

m = Mass of automobile = 1100 kg

v = Velocity of car = 120 km/h = $\dfrac{120}{3.6}\ \text{m/s}$

h = Height of hill = 80 m

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

Change in kinetic energy

$KE=\dfrac{1}{2}m(u^2-v^2)\\\Rightarrow KE=\dfrac{1}{2}\times 1100\times (0-(\dfrac{120}{3.6})^2)\\\Rightarrow KE=-611111.11\ \text{J}$

Change in kinetic energy is $-6111.11\ \text{kJ}$

Change in potential energy is given by

$PE=mgh\\\Rightarrow PE=1100\times 9.81\times 80\\\Rightarrow PE=863280\ \text{J}$

The change in potential energy is $863.28\ \text{kJ}$ .

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3 years ago

A DC generator turns at 2000 rpm and has an output of 200 V. The armature constant is 0.5 V-min/Wb, and the field constant of th

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Answer:

b. 10A

Explanation:

Using the formula, E= k × r×I

200= 0.5 ×2000×0.02×I

200=20×I

Dividing with 20

I = 200/20= 10A

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3 years ago

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