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gavmur [86]
3 years ago
9

Calculate the viscosity(dynamic) and kinematic viscosity of airwhen

Engineering
1 answer:
nikitadnepr [17]3 years ago
3 0

Answer:

(a) dynamic viscosity = 1.812\times 10^{-5}Pa-sec

(b) kinematic viscosity = 1.4732\times 10^{-5}m^2/sec

Explanation:

We have given temperature T = 288.15 K

Density d=1.23kg/m^3

According to Sutherland's Formula  dynamic viscosity is given by

{\mu} = {\mu}_0 \frac {T_0+C} {T + C} \left (\frac {T} {T_0} \right )^{3/2}, here

μ = dynamic viscosity in (Pa·s) at input temperature T,

\mu _0= reference viscosity in(Pa·s) at reference temperature T0,

T = input temperature in kelvin,

T_0 = reference temperature in kelvin,

C = Sutherland's constant for the gaseous material in question here C =120

\mu _0=4\pi \times 10^{-7}

T_0 = 291.15

\mu =4\pi \times 10^{-7}\times \frac{291.15+120}{285.15+120}\times \left ( \frac{288.15}{291.15} \right )^{\frac{3}{2}}=1.812\times 10^{-5}Pa-swhen T = 288.15 K

For kinematic viscosity :

\nu = \frac {\mu} {\rho}

kinemic\ viscosity=\frac{1.812\times 10^{-5}}{1.23}=1.4732\times 10^{-5}m^2/sec

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In a case where electrical current leakage from the circuit occurs, the GFCI would do the following:
Jobisdone [24]

Answer:

Sense the current leakage

Trip the circuit

Cut off the electricity

Explanation:

The correct order is -

Sense the current leakage

Trip the circuit

Cut off the electricity

Reason -

First step has to be taken to sense the electric current leakage without it being detected, it cant be dealt with.

The second step consists of tripping the  circuit so at to remove the flow of electricity.

The third step is to Cut the electricity off so to stop the leakage and be safe.

5 0
2 years ago
Can you reduce energy use without compromising people's basic needs (such as opening a car, cooking food, home lighting, electri
Liono4ka [1.6K]

Answer:

   yes

  • electric and/or hybrid cars
  • microwave ovens
  • LED lighting
  • low-power electronics

Explanation:

Advances in technology and changes in social organization have brought about reductions in energy use on many fronts.

  • hybrid/electric vehicles have reduced transportation energy needs
  • microwave ovens have reduced cooking energy needs
  • LED lighting has reduced lighting energy needs
  • low-power electronics have reduced the energy cost of technology and entertainment
  • heat pumps and insulated windows have reduced energy needs for home heating and cooling
  • zoning laws have reduced the need for travel to work and shopping areas
4 0
3 years ago
A cylindrical specimen of a hypothetical metal alloy is stressed in compression. If its original and final diameters are 30.00 a
IrinaVladis [17]

Answer:

The original length of the specimen l_{o} = 104.7 mm

Explanation:

Original diameter d_{o} = 30 mm

Final diameter d_{1} = 30.04 mm

Change in diameter Δd = 0.04 mm

Final length l_{1} = 105.20 mm

Elastic modulus E = 65.5 G pa = 65.5 × 10^{3} M pa

Shear modulus G = 25.4 G pa = 25.4 × 10^{3} M pa

We know that the relation between the shear modulus & elastic modulus is given by

G = \frac{E}{2(1 + \mu)}

25.5 = \frac{65.5}{2 (1 + \mu)}

\mu = 0.28

This is the value of possion's ratio.

We know that the possion's ratio is given by

\mu = \frac{\frac{0.04}{30} }{\frac{change \ in \ length}{l_{o} } }

{\frac{change \ in \ length}{l_{o} } = \frac{\frac{0.04}{30} }{0.28}

{\frac{change \ in \ length}{l_{o} } = 0.00476

\frac{l_{1} - l_{o}  }{l_{o}  } = 0.00476

\frac{l_{1} }{l_{o} } = 1.00476

Final length l_{o} = 105.2 m

Original length

l_{o} = \frac{105.2}{1.00476}

l_{o} = 104.7 mm

This is the original length of the specimen.

5 0
3 years ago
Answer back to question for la ,lot points
Lerok [7]

Answer:

yes

Explanation:

yes

5 0
2 years ago
If a signal is transmitted at a power of 250 mWatts (mW) and the noise in the channel is 10 uWatts (uW), if the signal BW is 20M
Bess [88]

Answer:

C = 292 Mbps

Explanation:

Given:

- Signal Transmitted Power P = 250mW

- The noise in channel N = 10 uW

- The signal bandwidth W = 20 MHz

Find:

what is the maximum capacity of the channel?

Solution:

-The capacity of the channel is given by Shannon's Formula:

                            C = W*log_2 ( 1 + P/N)

- Plug the values in:

                            C = (20*10^6)*log_2 ( 1 + 250*10^-3/10)

                            C = (20*10^6)*log_2 (25001)

                            C = (20*10^6)*14.6096

                           C = 292 Mbps

3 0
2 years ago
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