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hjlf
3 years ago
6

(a) the temperature on a warm summer day is 87 °f. what is the temperature in °c? (b) many scientific data are reported at 25

°c. what is this temperature in kelvins and in degrees fahrenheit? (c) suppose that a recipe calls for an oven temperature of 400 °f. convert this temperature to degrees celsius and to kelvins. (d) liquid nitrogen boils at 77 k. convert this temperature to degrees fahrenheit and to degrees celsius.
Chemistry
1 answer:
olchik [2.2K]3 years ago
8 0

Answers:

              (a)  30.55 °C

              (b) 298 K and 77°F

              (c)  204.44 °C and 477.44 K

              (d)  -320.8 °F and -196 °C

Explanation:

Converting °C into °F;

                                   °F  =  °C × 1.8 + 32

Converting °F into °C;

                                   °C  =  °F - 32 ÷ 1,8

Converting °C into K;

                                   K  =  °C + 273

Converting K into °C;

                                   °C  =  K - 273

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Write the equation for the neutralization reaction in which barium chloride is the salt formed. Show the reaction in which the f
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2 HCl + Ba(OH)₂ ⇒ BaCl₂ + 2 H₂O

Explanation:

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A mixture of methanol and methyl acetate contains 15.0 wt% methanol.
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The mixture flow rate in lbm/h = 117.65 lbm/h

<h3>Further explanation</h3>

Given

15.0 wt% methanol

The flow rate of the methyl acetate :100 lbm/h

Required

the mixture flow rate in lbm/h

Solution

mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :

\tt 15\%\times 200~kg=30~kg\\\\mol=\dfrac{mass}{MW}=\dfrac{30~kg}{32~kg/kmol}=0.9375~kmol

mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :

\tt 85\%\times 200=170~kg\\\\mol=\dfrac{170}{74}=2.297~kmol

Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.

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5 0
3 years ago
Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of
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Answer:

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Explanation:

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Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}

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The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0
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