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hram777 [196]
3 years ago
5

How is a compound similar to a homogenous mixture. how is it different

Physics
1 answer:
vivado [14]3 years ago
5 0
Similar because they're combined evenly through out and can't be separated easily. They're different because a compound contains only elements, but mixtures contain many different things. A compound has a chemical formula, but homo mixturedoesn't.
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The light that hits the surface of it is scattered.
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2 years ago
Write a small paragraph on how to determine the speed of sound using the time of flight method.
Makovka662 [10]

Answer:

time of flight of a pulse, and these most often

involve triggering of the measuring oscilloscope

with the signal that generates the sound pulse and

timing the time delay of the pulse picked up by a

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. Loren Winters

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.

Explanation:

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3 years ago
The space shuttle is located exactly half way between the earth and the moon. Which statement is true regarding the gravitationa
sdas [7]

Answer:

The correct answer is option B)

Explanation:

Considering the given question as -

The space shuttle is located exactly half way between the earth and the moon. Which statement is true regarding the gravitational pull on the shuttle? A) The moon pulls more on the shuttle. B) The earth pulls more on the shuttle. C) Both are equal due to equal distances. D) Both are equal due to the mass of the shuttle.

We know that gravitational pull (F) between any two bodies of mass M_{1} and M_{2} is given by -

F = \dfrac{GM_{1}M_{2} }{r^{2} } where 'r' is the distance between the two bodies.

Let ,

M_{e} : Mass of the earth

M_{m} : Mass of the moon

          m            : Mass of the satellite

r_{e}    : Distance of satellite from earth

r_{m}   : Distance of satellite from moon

Given that r_{e}=r_{m}

Let r_{e}=r_{m}=r

Force on satellite by the earth is -

F_{e} = \dfrac{GM_{e}m }{r^{2} }

Force on satellite by the moon is -

F_{m} = \dfrac{GM_{m}m }{r^{2} }

∵ Mass of earth (M_{e}) > Mass of moon (M_{m})

∴ F_{e} > F_{m}

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4 0
4 years ago
Which planet has a storm called the Great Dark Spot swirling in its atmosphere?
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Im thinking D. Neptune..
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4 years ago
Read 2 more answers
A single point charge is placed at the center of an imaginary cube that has 19 cm long edges. The electric flux out of one of th
OverLord2011 [107]

Answer:

The amount of charge at the center is -132.7 nC

Solution:

As per the question:

Electric flux from one face of cube, \phi_{E} = - 2.5 kN.m^{2}/C

Edge, a = 19cm

Since, a cube has six faces, thus total flux from all the 6 faces = 6\times (-2.5) = - 15 kN.m^{2}/C

Also, from Gauss' law:

\phi_{E,net} = \frac{1}{\epsilon_{o}}Q_{enc}

Q_{enc} = 8.85\times 10^{- 12}\times - 15\times 10^{3}

Q_{enc} = - 132.7 nC

3 0
3 years ago
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