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Alex73 [517]
3 years ago
8

If your car gets 30.3 mi/gal, how many gallons of gasoline would you use if you drove 506.3 miles? 1 mile = 5280 ft (exactly) In

clude one decimal place in your answer.
Chemistry
2 answers:
mr_godi [17]3 years ago
7 0

Answer : The number of gallons of gasoline needed are 16.7 gallons

Explanation :

As we are given that the car traveled 30.3 mi/gal. Now we have to determine the number of gallons of gasoline needed in 506.03 miles.

As, 30.3 miles car traveled in = 1 gallon

and, 1 miles car traveled in = \frac{1\text{ mile}}{30.3\text{mile}}\times 1 \text{ gallon}

So, 506.3 miles car traveled in = \frac{506.3\text{ mile}}{30.3\text{mile}}\times 1 \text{ gallon}

                                                    = 16.7 gallons

Therefore, the number of gallons of gasoline needed are 16.7 gallons

Salsk061 [2.6K]3 years ago
4 0

Answer: 16.7 gallon

Explanation:

Given: The car can drive 30.3 miles when 1 gallon of gasoline is used.

Distance covered = 506.3 miles

Thus for 30.3 miles, the amount of gasoline used= 1 gallon

For 506.3 miles, the amount of gasoline used=\frac{1}{30.3}\times 506.3=16.7gallon

Thus the amount of gasoline used is 16.7 gallons.


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Compare the root mean square speeds of O2 and UF6 at 65 degree Celsius
gayaneshka [121]
<h3>Answer:</h3>

The root mean square speeds of O₂ and UF₆ is 513m/s and 155 m/s respectively.

<h3>Solution and Explanation:</h3>
  • To find how fast molecules or particles of gases move at a particular temperature, the root  mean square speed is calculated.
  • Root mean square speed of a gas is calculated by using the formula;

       Root mean square=\sqrt{ \frac{3RT}{M}

       Where R is the molar gas constant, T is the temperature and M is the molar mass of gas in Kg.

<h3>Step 1: Root mean square speed from O₂</h3>

Molar mass of Oxygen is 32.0 g/mol or 0.032 kg/mol

Temperature = 65 degrees Celsius or 338 K

Molar gas constant = 8.3145 J/k.mol

Root mean square speed = \sqrt\frac{(3)(8.3145)(338K)}{0.032}

                                        = 513.289 m/s

<h3>Step 2: Root mean square speed of UF₆   </h3>

The molar mass of UF₆ is 352 g/mol or 0.352 kg/mol        

Root mean square speed = \sqrt\frac{(3)(8.3145)(338K)}{0.352}

                                                 = 154.762m/s

Therefore; the root mean square speeds of O₂ and UF₆ is 513m/s and 155 m/s respectively.

7 0
3 years ago
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