3.46410161514. i used a calculator so hopefully this is correct
Given:
wild turkey ; 12 in the first hour and cumulative number increases by 40% per hour
white-tail deer ; 18 in the first hour and 10 deer each hour after that.
wild turkery: 12 * (1.40)^n-1 ; n is the number of hour
white-tail deer: 18 + 10^n-1 ; n is the number of hour
n wild turkey white-tail deer
1 12 18
2 17 28
3 24 38
4 33 48
5 46 58
6 65 68
7 90 78
It would be hour 7 after sunrise that the cumulative count of the turkeys first exceed the cumulative count of the deer.
Answer:
-7>t
Step-by-step explanation:
If the temperature is lower than -7 degrees Fahrenheit, then the inequality must show a number less than -7. Or in other words, -7 is greater than what the temperature is, thus the answer is -7>t
I = Adt; where p = $290 is the Amount of the loan, d = 16% = 0.16 is the discount rate and t = 90days = 90/365 = 18/73 is the period.
I = 290 x 0.16 x 18/73 = 11.44
Interest = $11.44
Proceed = Amount - Interest = 290 - 11.44 = $278.56
Answer:
The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time.
Step-by-step explanation:
This is the right answer,since this result is only observed 21% of the time, so in general it's not significant, so the first 2 are eliminated. The 2 x 0.21 doesn't matter since, the percent is 21% not 42%, so it doesn't even matter. The last question we eliminate is:"The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 79% of the time" 79% of the time is a pretty good amount to say it's significant, but it only says 21% of the time.So, it leaves us with:The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time.
Hope this helps lol (: is this a psat or somethin?
