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tigry1 [53]
3 years ago
7

Identify the solute and the solvent used in this investigation.

Chemistry
1 answer:
Scilla [17]3 years ago
5 0
Solute is the nacl while the solvent is water [H2O]
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In one step in the synthesis of the insecticide Sevin, naphthol reacts with phosgene as shown.
Serhud [2]

Answer:

Explanation:

Chemical equation:

C₁₀H₈O + COCl₂  → C₁₁H₇O₂Cl + HCl

A. How many kilograms of C₁₁H₇O₂Cl form from 2.5×10*2 kg of naphthol?

Given data:

Mass of naphthol = 2.5 ×10² kg ( 250×1000 = 250000 g)

Mass of C₁₁H₇O₂Cl = ?

Solution:

Number of moles of naphthol = mass/ molar mass

Number of moles of naphthol = 250000 g/ 144.17 g/mol

Number of moles of naphthol = 1734.1 mol

Now we will compare the moles of naphthol with C₁₁H₇O₂Cl.

                     C₁₀H₈O       :         C₁₁H₇O₂Cl

                        1               :                1

                       1734.1         :             1734.1

Mass of C₁₁H₇O₂Cl:

Mass = number of moles × molar mass

Mass = 1734.1 mol × 206.5 g/mol

Mass = 358091.65 g

Gram to kilogram:

1 kg×358091.65 g/ 1000 g  = 358.1 kg

B. If 100. g of naphthol and 100. g of phosgene react, what is the theoretical yield of C11H7O2Cl?

Given data:

Mass of naphthol = 100 g

Mass of COCl₂ = 100 g

Theoretical yield of C₁₁H₇O₂Cl = ?

Solution:

Number of moles of naphthol:

Number of moles of naphthol = mass/ molar mass

Number of moles of naphthol = 100 g/ 144.17 g/mol

Number of moles of naphthol = 0.694 mol

Number of moles of phosgene:

Number of moles  = mass/ molar mass

Number of moles =  100 g/ 99 g/mol

Number of moles = 1.0 mol

Now we will compare the moles of naphthol and phosgene with C₁₁H₇O₂Cl.

                     C₁₀H₈O        :         C₁₁H₇O₂Cl

                        1                :                1

                       0.694        :              0.694

                    COCl₂          :             C₁₁H₇O₂Cl

                        1                :                1

                       1.0              :              1.0

The number of moles of C₁₁H₇O₂Cl produced by C₁₀H₈O are less so it will limiting reactant and limit the yield of  C₁₁H₇O₂Cl.

Mass of C₁₁H₇O₂Cl:

Mass = number of moles × molar mass

Mass =  0.694 mol × 206.5 g/mol

Mass = 143.3 g

Theoretical yield  =  143.3 g

C. If the actual yield of C11H7O2Cl in part b is 118 g, what is the percent yield?

Given data:

Actual yield of C₁₁H₇O₂Cl = 118 g

Theoretical yield = 143.3 g

Percent yield = ?

Solution:

Formula :

Percent yield = actual yield / theoretical yield × 100

Now we will put the values in formula.

Percent yield = 118 g/ 143.3 g × 100

Percent yield = 0.82 × 100

Percent yield = 82%

5 0
2 years ago
Protons have a positive charge true or false
aksik [14]

Answer:

True

Explanation:

Protons have a positive electrical of +1

6 0
2 years ago
Explain how the Law of Conservation of Mass is demonstrated In photosynthesis and cellular Respiration chemical equations. (Less
Oksi-84 [34.3K]

Explanation:

  • According to the law of conservation of mass, In a chemical reaction, mass is neither created nor destroyed. In other words, the total mass for the reactants needs to equal the total mass of the products.
  • <u><em>In photosynthesis the reactants are 6 carbon dioxide, 6 water and sunlight. The mass of these reactants adds to equal the mass of the products, which are 1 glucose and 6 oxygen. </em></u>
  • <u><em>Cellular respiration on the other hand uses glucose and oxygen gas to produce water, carbon dioxide, and a usable form of energy known as ATP.</em></u>
  • Cellular respiration is the opposite of photosynthesis, such that the products of photosynthesis are the reactants of cellular respiration. Cellular respiration also obeys the law of conservation of mass.
6 0
3 years ago
A cell has lost the ability to release energy from glucose for the cell to use. In which of the following cell structures would
Irina-Kira [14]

Answer:

b

Explanation:

b? i think

7 0
3 years ago
Read 2 more answers
A student was given a pale blue transparent liquid in a beaker. The student gently heated the solution until the liquid had vapo
Vikki [24]
This is so as the liquid you are heating is copper (II) sulfate (I think so) so when you heat it to saturation, there will still be some water molecules left behind, which will allow copper (II) sulfate crystals to be formed since there is water of crystallisation. so the formula is (CuSO4.5H2O).

Hence, if you heat it for a longer period of time when all the water has evaporated, you will obtain a white powder (CuSO4) as crystals cannot form without water of crystallisation
3 0
3 years ago
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