Protons have a positive charge true or false

Chemistry

1 answer:

aksik [14]2 years ago

6 0

Answer:

True

Explanation:

Protons have a positive electrical of +1

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Octanol is slightly soluble in water, and water is very soluble in octanol. why is it important to presaturate octanol with wate

notsponge [240]

N-Octanol and water are chosen because the connection between a substance's hydrophilicity and lipophilicity is measured by $K_{OW}$ (n-Octanol/Water partition coefficient). When a chemical is more dissolves in fat-like solvents like n-octanol, the value is more significant than one, when it's more dissolved in water, the value is lower.

What is the partition coefficient?

The partition coefficient for the two-phase network comprising n-octanol and water is known as the $K_{OW}$ value. N-Octanol-Water Partition Ratio is another name for it.

The connection between a substance's hydrophilicity (its ability to dissolve in water) and lipophilicity (its ability to dissolve in fat) is measured by $K_{OW}$ . The value is bigger if a drug is more accessible in fat-like liquids like n-octanol and less if a compound seems more water-soluble.

Owing to linkage or fragmentation, substances that are involved in the octanol-water combination as multiple synthetic entities are each given a unique $K_{OW}$ ratio.

So, N-Octanol is chosen because it has a carbon/oxygen ratio that is comparable to that of lipids and because it shows both hydrophobic and hydrophilic properties. N-octanol, therefore, resembles the makeup and characteristics of cells and other living things.

Learn more about octanol here:

brainly.com/question/7768749

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7 months ago

The molecule with the largest dipole moment (a) co2 (b) h2o (c) ch4 (d) c2h4 (e) ph3

storchak [24]

The molecule with the largest dipole moment will be $CH_{4}$ .

A dipole moment would be a unit used to describe how far apart two electrical charges are from one another. Dipole moments represent a type of vector. The direction could be from negative charge to positive charge, while the magnitude has been equal to the charge times the distance between most of the charges.

The polar bonds, of $CO_{2}$ as well as $H_{2} O$ have chemical configurations where the polarity cancels, leaving no net dipole. Regardless of the molecule's shape, $CH_{4}$ lacks a net dipole due to its non-polar links.