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MAXImum [283]
3 years ago
5

How can you write c6h12o6 in the simplest form that illustrates the proportion of elements in monosaccharides?

Chemistry
2 answers:
VikaD [51]3 years ago
5 0
The answer is
(CH2O)6
makvit [3.9K]3 years ago
4 0

<u>Answer:</u> The simplest formula for monosaccharides is (CH_2O)_6;n=6

<u>Explanation:</u>

Monosaccharides are defined as the sugars that are present in the simplest forms or which cannot be further hydrolyzed. They are the the basic units os sugar.

This class of sugars consist of carbon atoms, hydrogen atoms and oxygen atoms.

The general formula for a monosaccharide is (CH_2O)_n;n\geq 3

We are given a sugar having chemical formula C_6H_{12}O_6

So, the simplest form of the given sugar will be (CH_2O)_6;n=6

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The two sides of the equation should be
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Answer:

Hey mate.....

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8 0
3 years ago
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How many moles of H2O can be produced with 5.8 moles of O2 ?
Evgesh-ka [11]

Answer:

1.78

Explanation:

1mole produce 18g/x will produce 32g then the answer is 1.78moles

8 0
2 years ago
Để pha 2 lít dung dịch H2SO4 0,1N từ axit đặc 98% (d 1.84g/ml). Cần lấy bao nhiêu ml acid đặc
Ivanshal [37]

Answer:

Cm = Cn/n = 0.1/2 = 0.05 (M)

n = 0.05*2= 0.1 mol

m H2SO4= 0.1*98= 9.8 g

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Explanation:

5 0
2 years ago
Determine the number of moles in 258.45 grams of iron (III) chloride (FeCl3). Show and explain all
QveST [7]

Answer:

\boxed {\boxed {\sf 1.5935 \ mol \ FeCl_}}

Explanation:

To convert from grams to moles, we must use the molar mass. This can be found on the Periodic Table. First, find the molar mass of iron and chlorine.

  • Fe: 55.84 g/mol
  • Cl: 35.45 g/mol

Check the formula. There is a subscript of 3 after Cl, so there are 3 atoms of chlorine in 1 molecule. Multiply iron's molar mass by 3, then add iron's molar mass.

  • FeCl₃: 55.84 + 3(35.45) = 55.84+106.35=162.19 g/mol

Use this number as a ratio.

\frac {162.19 \ g\ FeCl_3}{1 \ mol \ FeCl_3}

Multiply by the given number of grams.

258.45 \ g \ FeCl_3 *\frac {162.19 \ g\ FeCl_3}{1 \ mol \ FeCl_3}

Flip the ratio so the grams of iron (III) chloride cancel.

258.45 \ g \ FeCl_3 *\frac {1  \ mol \ FeCl_3}{162.19 \ g\ FeCl_3}

258.45  *\frac {1  \ mol \ FeCl_3}{162.19}

\frac {258.45  \ mol \ FeCl_3}{162.19}

1.59350144892 \ mol \ FeCl_3

The original measurement of grams has 5 significant figures, so our answer must have the same. For the number we calculated, that is the ten thousandth place.

1.5935 \ mol \ FeCl_3

258.45 grams is approximately 1.5935 moles of iron (III) chloride.

3 0
3 years ago
Describe the relative orientations of the orbitals related to an atom's 2p sublevel.
iris [78.8K]
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