Answer: 0.77 mole
Explanation:
Atomic mass of Ca = 40g/mol
Atomic mass of O = 16g/mol
Atomic mass of H = 1
Therefore,
1 mole of Ca(OH)_2 contains
40+[16+1]2
= 40+34
=74g/mole
Hence,
1 mole of Ca(OH)_2 = 74g
Let x mole of Ca(OH)_2 = 56. 78
x = 56.78/74
x = 0.77 mole
Answer:
C
Explanation:
cold thinks sink and are more dense, warm things rise and are less dense
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If two shells overlap, they start to share electrons and thus, a bond is formed
Answer:
Option A. 2, 3, 2
Explanation:
We'll begin by balancing the equation. This can be achieved by doing the following:
Fe + Cl2 —> FeCl3
There are 2 atoms of Cl on the left side and 3 atoms on the right side. It can be balance by putting 3 in front of Cl2 and 2 in front of FeCl3 as shown below:
Fe + 3Cl2 —> 2FeCl3
There are 2 atoms of Fe on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Fe as shown below:
2Fe + 3Cl2 —> 2FeCl3
Now the equation is balanced.
The coefficients are : 2, 3, 2
Answer:
The mass percent of aluminum sulfate in the sample is 16.18%.
Explanation:
Mass of the sample = 1.45 g
Mass of the precipitate = 0.107 g
Moles of aluminum hydroxide = 
According to reaction, 2 moles of aluminum hydroxide is obtained from 1 mole of aluminum sulfate .
Then 0.001372 moles of aluminum hydroxide will be obtained from:
Mass of 0.000686 moles of aluminum sulfate :
= 0.000686 mol × 342 g/mol = 0.2346 g
The mass percent of aluminum sulfate in the sample:
