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2 years ago

The two sides of the equation should be

Chemistry

2 answers:

KonstantinChe [14]2 years ago

8 0

Answer:

Hey mate.....

Explanation:

This is ur answer.....

---> Equal

hope it helps,

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ZanzabumX [31]2 years ago

5 0

Answer:

I am not quite sure if this is what you are looking for but each side of the equation should be equivalent.

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What happens if a species is unable to adapt to a changing environment.

enot [183]

The awnser your looking for would be B: It's Population decreases. Because if a species is unable to adapt to a changing environment the species would either have to move away or they could die in that location.

4 0

2 years ago

What is the variable for the equilibrium constant Re K Ec E

Nitella [24]

Answer: I am pretty sure it is E

Explanation:

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2 years ago

Which isomer of 1-bromo-2-tert-butylcyclohexane reacts faster when refluxed with potassium tert-butoxide?Draw the structure of t

ivolga24 [154]

Answer:

See explanation and image attached

Explanation:

The reaction of 1-bromo-2-tert-butylcyclohexane with potassium tert-butoxide is an elimination reaction that occurs by E2 mechanism.

The E2 reaction proceeds faster when the hydrogens are in an antiperiplanar position at an angle of 180 degrees.

This is only attainable in the trans isomer of 1-bromo-2-tert-butylcyclohexane. Hence trans 1-bromo-2-tert-butylcyclohexane reacts faster with potassium tert-butoxide

8 0

3 years ago

A 9.79 mol sample of freon gas was placed in a balloon. Adding 3.50 mol of freon gas to the balloon increased its volume to 21.8

aivan3 [116]

Answer:

16.06 L was the initial volume of the balloon.

Explanation:

Initial moles of freon in ballon = $n_1=9.79 mol$

Initial volume of freon gas in ballon = $V_1=?$

Moles of freon gas added in the balloon = n = 3.50 mole

Final moles of freon in ballon = $n_2=n_1+n=9.79 mol+3.50 mol=13.29 mol$

Final volume of freon gas in ballon = $V_2=21.8 L$

Using Avogadro's law:

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$ ( at constant pressure and temperature)

$V_1=\frac{V_2\times n_1}{n_2}=\frac{21.8 L\times 9.79 mol}{13.29 mol}=16.06L$

16.06 L was the initial volume of the balloon.

4 0

2 years ago

Can sedimentation and decantation be used for all types of mixtures? Explain

Bumek [7]

Explanation:

1. Sedimentation and decantation cannot be used for all types of mixtures.

Decantation is a separation technique in which is used to separate immiscible liquids or mixtures containing liquid and solids within them.

In decantation, gravity is used to bring the denser materials to settle at the bottom.

For homogenous mixtures, it is not possible to use decantation. A solution of sugar and water will not decant.

2. Yes, mass of an object reduces the settling time of such object in a mixture.

The higher the mass, the faster the rate of settling. Also, as we know, mass is directly proportional to density. A body with a high density will settle faster in solution.

4 0

2 years ago