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I am Lyosha [343]
3 years ago
14

Determine the number of moles in 258.45 grams of iron (III) chloride (FeCl3). Show and explain all

Chemistry
1 answer:
QveST [7]3 years ago
3 0

Answer:

\boxed {\boxed {\sf 1.5935 \ mol \ FeCl_}}

Explanation:

To convert from grams to moles, we must use the molar mass. This can be found on the Periodic Table. First, find the molar mass of iron and chlorine.

  • Fe: 55.84 g/mol
  • Cl: 35.45 g/mol

Check the formula. There is a subscript of 3 after Cl, so there are 3 atoms of chlorine in 1 molecule. Multiply iron's molar mass by 3, then add iron's molar mass.

  • FeCl₃: 55.84 + 3(35.45) = 55.84+106.35=162.19 g/mol

Use this number as a ratio.

\frac {162.19 \ g\ FeCl_3}{1 \ mol \ FeCl_3}

Multiply by the given number of grams.

258.45 \ g \ FeCl_3 *\frac {162.19 \ g\ FeCl_3}{1 \ mol \ FeCl_3}

Flip the ratio so the grams of iron (III) chloride cancel.

258.45 \ g \ FeCl_3 *\frac {1  \ mol \ FeCl_3}{162.19 \ g\ FeCl_3}

258.45  *\frac {1  \ mol \ FeCl_3}{162.19}

\frac {258.45  \ mol \ FeCl_3}{162.19}

1.59350144892 \ mol \ FeCl_3

The original measurement of grams has 5 significant figures, so our answer must have the same. For the number we calculated, that is the ten thousandth place.

1.5935 \ mol \ FeCl_3

258.45 grams is approximately 1.5935 moles of iron (III) chloride.

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<span>You can see that there are 2 moles of gas in the reactants and 3 moles of gas in the products. </span>

<span>1 moles of ideal gas occupies the same volume as 1 mole of any other ideal gas under the same conditions of temp and pressure. </span>

<span>Since it is done under constant temp and pressure that means the volume change will be equal to the volume of 1 mole of gas </span>

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<span>- the gas constant is different for different units of temp and pressure (see wikki link) in this case temp and pressure are constant, and we want to put the result in an equation that has Joules in it, so we select 8.314 JK^-1mol^-1) </span>
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