Voltage = N * Δ(BA)/Δt
<span>BA = 0.57*0.16*0.22 = 2.0064e-2 </span>
<span>N = 505 </span>
<span>115/505 = Δ(BA)/Δt = 23/101 </span>
<span>When the top of the coil rotates to the bottom (1/2 half cycle) BA changes from max to min and when the bottom rotates back to the top BA changes from min to max. So Δ(BA) is twice per cycle </span>
<span>So 2*101Δ(BA)=23Δt and Δt = 1/f </span>
<span>202*2.0064e-2/23 =Δt = 1/f => f =5.675Hz</span>
Newtons first law of motion
object in motion stays in motion, object at rest stays at rest unless acted upon an unbalanced force
Answer:
Nebula
Explanation:
Given that in the constellation of Orion, you can see a group of stars and other objects that appear in the shape of a sword. Ln the middle of the sword, a bright "fuzzy star" appears. Astronomers looking at this object through telescopes refer to it as a "stellar nursery." Another name for this object is called NEBULA.
The space where new stars are forming anew is known as nebulae
Answer:
191.36 N/m
Explanation:
From the question,
The Potential Energy of the safe = Energy of the spring when it was compressed.
mgh = 1/2ke²............... Equation 1
Where m = mass of the safe, g = acceleration due to gravity, h = height of the save above the heavy duty spring , k = spring constant, e = compression
Making k the subject of the equation,
k =2mgh/e²................ Equation 2
Given: m = 1100 kg, h = 2.4 mm = 0.0024 m, e = 0.52 m
Constant: g = 9.8 m/s²
Substitute into equation 2
k = 2(1100)(9.8)(0.0024)/0.52²
k = 51.744/0.2704
k = 191.36 N/m
Hence the spring constant of the heavy-duty spring = 191.36 N/m
