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3 years ago

Square root of -100= _+_

Mathematics

2 answers:

andrew-mc [135]3 years ago

6 0

Answer:

-10i

Step-by-step explanation:

Leno4ka [110]3 years ago

3 0

Answer:

The answer i belevie should be 10i

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

I hope this helps

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WILL GIVE BRAINLIEST. please help

kondor19780726 [428]

Answer:

x = 11.4 m

y = 21 m

man's shadow = 9.6 m

Step-by-step explanation:

measure of third angle must be 50 degrees (180 - (40 + 90))

you can take tan50° = 15/y and 'y' will equal approx. 21

to find 'x' you can take tan21° = (21-x) /25 and 21 - x = 25 · tan21°

21 - x = 9.6

-x = -11.4

x = 11.4

man's shadow is the difference of 21 and 11.4, which is 9.6

4 0

3 years ago

Simplify by using the distributive property and then combining like terms for the expression 7(2x+3)

max2010maxim [7]

Answer:

14x+21

Step-by-step explanation:

7*2x=14x

7*3=21

14x+21

hope this helps :9

6 0

3 years ago

-2/9 - (-1/3 divided 3/5) PLEASE HURRYY

charle [14.2K]

Answer:

1/3

Step-by-step explanation:

-1/3 divided by 3/5 = -5/9

-2/9 - -5/9 = 1/3

6 0

3 years ago

Read 2 more answers

What is the completely factored form of f(x)=x^3-7x^2+2x+4

xxMikexx [17]

$Solution, \mathrm{Factor}\:x^3-7x^2+2x+4:\quad \left(x-1\right)\left(x^2-6x-4\right)$

$Steps:$

$x^3-7x^2+2x+4$

$Use\:the\:rational\:root\:theorem,\\a_0=4,\:\quad a_n=1,\\\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:4,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\\\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:4}{1},\\\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x-1,\\\left(x-1\right)\frac{x^3-7x^2+2x+4}{x-1}$

$\frac{x^3-7x^2+2x+4}{x-1}$

$\mathrm{Divide}\:\frac{x^3-7x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}x^3-7x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{x^3}{x},\\\mathrm{Quotient}=x^2,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}x^2:\:x^3-x^2,\\\mathrm{Subtract\:}x^3-x^2\mathrm{\:from\:}x^3-7x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-6x^2+2x+4,\\Therefore,\\\frac{x^3-7x^2+2x+4}{x-1}=x^2+\frac{-6x^2+2x+4}{x-1}$

$\mathrm{Divide}\:\frac{-6x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-6x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-6x^2}{x}=-6x,\\\mathrm{Quotient}=-6x,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-6x:\:-6x^2+6x,\\\mathrm{Subtract\:}-6x^2+6x\mathrm{\:from\:}-6x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-4x+4,\\\mathrm{Therefore},\\\frac{-6x^2+2x+4}{x-1}=-6x+\frac{-4x+4}{x-1}$

$\mathrm{Divide}\:\frac{-4x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-4x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-4x}{x}=-4,\\\mathrm{Quotient}=-4,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-4:\:-4x+4,\\\mathrm{Subtract\:}-4x+4\mathrm{\:from\:}-4x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=0,\\\mathrm{Therefore},\\\frac{-4x+4}{x-1}=-4$

$\mathrm{The\:Correct\:Answer\:is\:\left(x-1\right)\left(x^2-6x-4\right)}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

8 0

3 years ago

On a hiking trip,LaShana notes that she hikes about 12 kilometers every 4 hours .If she continues at this rate,use a ratio table

Evgesh-ka [11]

12 : 4 = 3 km her speed per hour
3 * 6 = 18 km she could hike in 6 hours

4 0

4 years ago