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3 years ago

Note the degree x^3+x+x^2-2-x^3

Mathematics

1 answer:

iren [92.7K]3 years ago

8 0

Answer:

2nd degree

Step-by-step explanation:

can't be x^3 because that cancels out, so the next highest one is x^2

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What is -1 11/12 in it’s simplest form

Dafna1 [17]

Answer: - 23/12

decimal -1.916

Step-by-step explanation:

3 0

4 years ago

Choose the missing exponent to create a polynomial?

lions [1.4K]

3.

The answers 2 and 4 are incorrect because inserting that ad the missing exponent would create only a trinomial.

-9 is incorrect as it would create something more than a polynomial. 7 is incorrect as, if doing a certain type of division, would result in a larger polynomial.

Hope this helps!

5 0

3 years ago

Please help -3/4(8n + 12) = 3(n-3)

Dennis_Churaev [7]

Step-by-step explanation:

$- \frac{3}{4} (8n + 12) = 3(n - 3)$

$- 3(8n + 12) = 12(n - 3)$

$\cancel{- 3}(8n + 12) = \cancel{12}(n - 3)$

$- (8n + 12) = 4(n - 3)$

$- 8n - 12 = 4n - 12$

$- 8n - 4n = - 12 + 12$

$- 12n = 0$

$n = 0$

8 0

3 years ago

Simplify the following expression into the form a + bi, where a and b are rational numbers.

vagabundo [1.1K]

The answer is -16 - 10i.

Using the distributive property on the first part, we have:
-2i*7--2i*4i + (3+i)(-2+2i)
-14i+8i² +(3+i)(-2+2i)

Using FOIL on the last part,
-14i+8i²+(3*-2+3*2i+i*-2+i*2i)
-14i+8i²-6+6i-2i+2i²
-10i+8i²-6+2i²

Since we know that i = -1,
-10i+8(-1)-6+2(-1)
-10i-8-6-2
-16-10i

7 0

3 years ago

Read 2 more answers

Urgent. There are 12 coloured counters in a bag. The counters are black, white or grey A counter is chosen at random. The probab

Nastasia [14]

Answer:

1/12

Step-by-step explanation:

Needed information

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

The sum of the probabilities of all outcomes must equal 1

Solution

We are told that the probability that the counter is not black is 3/4.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is black by subtracting 3/4 from 1:

$\sf P(counter\:not\:black)=\dfrac34$

$\implies \sf P(counter\:black)=1-\dfrac34=\dfrac14$

We are told that the probability that the counter is not white is 2/3.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is white by subtracting 2/3 from 1:

$\sf P(counter\:not\:white)=\dfrac23$

$\implies \sf P(counter\:white)=1-\dfrac23=\dfrac13$

We are told that there are black, white and grey counters in the bag. We also know that the sum of the probabilities of all outcomes must equal 1. Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

$\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}$

7 0

2 years ago