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Elan Coil [88]
3 years ago
8

The amount of power has decreased. This is most likely the result of less work being done over a longer period of time.

Physics
2 answers:
Oxana [17]3 years ago
8 0
The first option is the most correct.
melisa1 [442]3 years ago
3 0

Answer:

Option (A)

Explanation:

Power is defined as the rate of doing work.

Or

The work done in unit time is defined as the power.

The formula for the power is given  by

Power = \frac{Work}{Time}

Power is a scalar quantity and its SI unit is Watt.

As the power is decreased, either work is decreased or time is increased.

So, if a less work is done in a longer period of time, the power is decreased.

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A small cube of metal measures 19.0 mm on a side and weighs 79.6 g. What is the density of the metal in g/cm3?
Nady [450]

Answer:

density of cube =11.605 g/cm³

Explanation:

density of a substance is the mass per unit volume of that substance.

the density of a substance = \frac{mass}{volume}

volume of a cube = l³,

l = 19.0mm , lets convert mm to cm

1mm = 0.1cm, thus, 19mm =19*0.1 =1.9cm

length of cube =1.9cm

volume of cube = 1.9³

density of cube = \frac{79.6}{1.9^{3} }

density of cube =11.605 g/cm³

8 0
3 years ago
Based on the free-body diagram, the net force acting<br> on this firework is
Strike441 [17]

0N. The net force acting on this firework is 0.

The key to solve this problem is using the net force formula based on the diagram shown in the image. Fnet = F1 + F2.....Fn.

Based on the free-body diagram, we have:

The force of gases is Fgases = 9,452N

The force of the rocket Frocket = -9452

Then, the net force acting is:

Fnet = Fgases + Frocket

Fnet = 9,452N - 9,452N = 0N

4 0
2 years ago
Read 2 more answers
Learning Task 2: Prepare a basin with half-filled water and stone. Drop a stone
ELEN [110]

Answer:

1 . What happens when you drop the stone?

Depending on the weight from which the stone was dropped, the glass might well break

2 depending on the size and weight and shape on the stone the glass might well break

3 depending on the density on the stone the stone might when float on the water

Explanition :

GIVE ME BRAINLESS PLEASE !!

6 0
2 years ago
How many electrons must be removed from each of two 5.69-kg copper spheres to make the electric force of repulsion between them
CaHeK987 [17]

Answer:

n=3.056*10^{9} Electrons

Explanation:

Please see attached file

7 0
3 years ago
Planet a and planet b are in circular orbits around a distant star. planet a is 7.8 times farther from the star than is planet
gogolik [260]
To find the ratio of planetary speeds Va/Vb we need the orbital velocity formula: 

V=√({G*M}/R), where G is the gravitational constant, M is the mass of the distant star and R is the distance of the planet from the star it is orbiting. 

So Va/Vb=[√( {G*M}/Ra) ] / [√( {G*M}/Rb) ], in our case Ra = 7.8*Rb 

Va/Vb=[ √( {G*M}/{7.8*Rb} ) ]  / [√( {G*M}/Rb )], we put everything under one square root by the rule: (√a) / (√b) = √(a/b) 

Va/Vb=√ [ { (G*M)/(7.8*Rb) } / { (G*M)/(Rb) } ], when we cancel out G, M and Rb we get:

Va/Vb=√(1/7.8)/(1/1)=√(1/7.8)=0.358 so the ratio of Va/Vb = 0.358.  
6 0
3 years ago
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