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3 years ago

Which is a homogeneous mixture?

Chemistry

1 answer:

Goshia [24]3 years ago

6 0

Answer & Explanation:

A homogeneous mixture is a (solid, liquid, or gaseous) mixture that has the same ratios of its components in any given sample.
On the other hand, a heterogeneous mixture has components whose proportions are different throughout the sample.
"Homogeneous" and "heterogeneous" are not absolute terms but depend on context and the size of the sample.
In chemistry, a homogeneous suspension of material means that when dividing the volume in half, the same amount of material is suspended in both halves of the substance; however, it might be possible to see the particles under a microscope.
An example of a homogeneous mixture is air.

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3 years ago

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3 years ago

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4 years ago

Balance the following chemical equation

ratelena [41]

Answer:

Explanation:

4). Ca(NO₃)₂ + Na₂SO₄ → CaSO₄ + 2Na(NO₃)₂

This question is incorrect.

Since, the final product by reacting Na⁺⁺ and NO₃⁻⁻ is NaNO₃

Correct equation will be,

Ca(NO₃)₂ + Na₂SO₄ → CaSO₄ + 2NaNO₃

This equation is in the balanced form.

5). Ni(NO₃)₂ + KI → NiI + 2K(NO₃)₂

Correct equation will be,

Ni(NO₃)₂ + KI → NiI₂ + 2KNO₃

[Since final product by reacting Ni⁺⁺ and I⁻ is NiI₂]

Balanced form of this equation will be,

Ni(NO₃)₂ + 2KI → NiI₂ + 2KNO₃

6). Ni(NO₃)₂ + KOH → NiOH + K(NO₃)₂

Correct form of the equation will be

Ni(NO₃)₂ + KOH → Ni(OH)₂ + KNO₃

[Since reaction of Ni⁺⁺ and OH⁻ gives Ni(OH)₂ and the reaction of K⁺ and NO₃⁻ gives KNO₃]

Now balancing this equation,

Ni(NO₃)₂ + KOH → Ni(OH)₂ + 2KNO₃

↓

Ni(NO₃)₂ + 2KOH → Ni(OH)₂ + 2KNO₃

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4 years ago

If you complete and balance the following oxidation-reduction reaction in basic solution NO2−(aq) + Al(s) → NH3(aq) + Al(OH)4−(a

andreev551 [17]

Answer:

NO2- + 5H2O + 2Al + OH- → NH3 + 2Al(OH)4-

There is 1 hydroxide ion, on the reactant side

Explanation:

NO2−(aq) + Al(s) → NH3(aq) + Al(OH)4−(aq)

Step 1: The half reactions

NO2- (aq) → NH3(g)

Al(s) → Al(OH)4-

Step 2: Balancing electrons

NO2- → NH3

On the left side N has an oxidation number of +3 and on the right side -3.

NO2- +6e-→ NH3

Al(s) → Al(OH)4-

On the left side, Al has an oxidation number of 0 and on the right side +3.

Al(s) → Al(OH)4- +3e-

To have the same amount of electrons transfered, we have to multiply the second reaction by 2

NO2- +6e-→ NH3

2(Al(s) → Al(OH)4- +6e-)

Step 3: Balance with OH/H2O

NO2- +6e +5H2O → NH3 +7OH-

2Al +8OH- → 2Al(OH)4- + 6e-

Step 4: The netto reaction

NO2- + 5H2O + 2Al + 8OH- → NH3 +7OH- + 2Al(OH)4-

NO2- + 5H2O + 2Al + OH- → NH3 + 2Al(OH)4-

There is 1 hydroxide ion, on the reactant side

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4 years ago