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Alja [10]
3 years ago
10

What is a unicellular organism?

Chemistry
2 answers:
Schach [20]3 years ago
3 0
An organism that consists of one cell
Paul [167]3 years ago
3 0
The answer is D An organism that consist of one cell
You might be interested in
Calculate the equilibrium constant K for the following reaction: H2(g) +
SIZIF [17.4K]

Answer:

192.9

Explanation:

From the question,

Ke = [HCL]²/[H₂][CL₂].......................... Equation 1

Where Ke = Equilibrium constant.

Given: [HCL] = 0.0625 M, [H₂] = 0.0045 M, [CL₂] = 0.0045 M

Substitute these values into equation 1

Ke = (0.0625)²/(0.0045)(0.0045)

ke = (3.90625×10⁻³)/(2.025×10⁻⁵)

ke = 1.929×10²

ke = 192.9

Hence the equilibrium constant of the system = 192.9

5 0
3 years ago
How were weapons and utensils fashioned during the Stone Age
Alenkasestr [34]
They were created with stone and wood and sometimes even bones, I hope this helped!
4 0
3 years ago
When the pressure that a gas exerts on a sealed container changes from 1100 bar to 75.5 bar, the temperature changes from k to 2
Serjik [45]
Gay-Lussac's law gives the relationship between pressure and temperature of gas. For a fixed amount of gas, pressure is directly proportional to temperature at constant volume.
P/T = k
where P - pressure , T - temperature and k - constant
\frac{P1}{T1} =  \frac{P2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting the values in the equation 
\frac{1100 bar}{T}  =  \frac{75.5 bar}{298 K}
T = 4342 K
initial temperature was 4342 K
7 0
3 years ago
The reaction A → products is first order. If the initial concentration of A is 0.646 M and, after 72.8 seconds have elapsed, the
mario62 [17]

Answer: 0.00867 moldm-3

Explanation:

Since the reaction is 1st order,

Rate of reaction=∆[A]÷t

0.646-0.0146/72.8= 0.00867

Remember that in a first order reaction, the rate of reaction depends on change in the concentration of only one of the reaction species, A in the problem above.

5 0
3 years ago
How many moles of oxygen are in 25.45 g of caco3?
emmainna [20.7K]
From the periodic table:
mass of oxygen = 16 grams
mass of calcium = 40 grams
mass of carbon = 12 grams
mass of CaCO3 = 40 + 12 + 3(16) = 100 grams
Therefore, each 100 grams of CaCO3 contains 3 moles of oxygen
To know the number of oxygen moles in 25.45 grams, we will simply do cross multiplication as follows:
number of oxygen moles = (25.45 x 3) / 100 = 0.7636
3 0
3 years ago
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