A half life of 29 years means that after 29 years, only half of this isotope would be left due to radioactive decay. If we start of with 2000g of it and leave it for 116 years, it would undergo 4 "half=lives". 116/29 = 4. So after the first half life, we would have 2000g/2 = 1000g left. After the second, we would have 500g left, after the third, 250g so after 4 half lives or 116 years, there would be 125 g of Strontium-90 left at the site.
Brick-red because the most reducing sugar reduces the blue copper salts -that are present in Benedict's solution- to a red compound.
Explanation:
A stable isotope is one that does not emit radiation, or, if it does its half-life is too long to have been measured. It is believed that the stability of the nucleus of an isotope is determined by the ratio of neutrons to protons.
Hope this helps you out : D
<span>Since the answer is in grams, kilograms must first be converted to grams. A kilogram is equivalent to 1000 grams. Therefore, multiply 1.2 kilograms by 1000 and you get 1,200 grams. Then, calculate the number of hours in 5 days. Each day is 24 hours and 24 hours multiplied by 5 days equals 120 hours. Lastly, since the answer is in grams per hour, divide 1,200 grams by 120 hours and the resultant rate of reaction is 10 g/hr.</span>
Answer:
Mass of KNO3= 10g
Molar mass of KNO3 = 101.1032g/mol
Volume = 250ml = 0.25L
No of mole on of KNO3 = mass of KNO3/Molar mass of KNO3
no of mole of KNO3 = 10/101.1032
No of mole of KNO3 = 0.09891
molarity of KNO3 = no of mole of KNO3/Vol (L)
Molarity = 0.09891/0.25 = 0.3956M
Molarity of KNO3 = 0.3956M