Using the Theorem of Pythagoras (a² + b² = c²)
Put in the values:
12² + 12² = 28²
Is it correct? (solve)
Nope! Because 12² + 12² = 288, and the square root of 288 is about 17, not 28.
The answer is no, 12cm, 12cm, 28cm cannot form a triangle.
Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)
Part A:
Consider from x = -5 to x = -4, they are 1 unit apart and the difference of their outputs is given by:
-3 - (-11) = -3 + 11 = 8.
Thus, the value of the output increases by 8 units for each one unit increase in the input.
Part B:
Consider from x = -3 to x = -1, they are 2 units apart and the difference of their outputs is given by:
21 - 5 = 16.
Thus, the value of the output increases by 16 units for each two units increase in the input.
Part C:
Consider from x = 0 to x = 3, they are 3 units apart and the difference of their outputs is given by:
53 - 29 = 24.
Thus, the value of the output increases by 24 units for each three units increase in the input.
Part D:
It can be noticed that the ratio difference in the outputs to the input intervals are equal for all the given input intervals.
i.e 8 / 1 = 16 / 2 = 24 / 3.
I cant hardly see it ,what's the question?
The true statements about the triangles RST and DEF are: (a), (d) and (e)
<h3>How to determine the true statements?</h3>
The statement ΔRST ≅ ΔDEF means that the triangles RST and DEF are congruent.
This above implies that:
- The triangles can be mapped onto each other by rigid transformations such as reflection, translation and rotation
- The transformation does not include dilation
- Corresponding sides are congruent
The above means that the possible true statements are: (a), (d) and (e)
Read more about transformation at:
brainly.com/question/4289712
#SPJ1
Parallel means that the two equations have the same slope,
so we have y = 8x + b so far.
Then we can just apply the slope to the given point by taking the y value and decreasing it by 40, due to the x value being 5
So in short, the equation that runs parallel to y = 8x-8 and intersect the point (5,2) is y = 8x -38
