Answer:
θ = 26.6°
Explanation:
Formula for maximum height is;
h = u²sin²θ/2g
We are told maximum height is 25 m, thus;
u²sin²θ/2g = 25 - - - - (eq 1)
Formula for horizontal range is;
R = u²sin2θ/g
In Mathematics, sin2θ = 2sinθcosθ
So; R = 2u²sinθcosθ/g
R = 2u²sinθcosθ/g
We are given Horizontal range = 200 m.
Thus;
2u²sinθcosθ/g = 200 - - - - (eq 2)
Divide eq 1 by eq 2 to get;
200/25 = 4cosθ/sinθ
8 = 4cosθ/sinθ
4/8 = sinθ/cosθ
0.5 = tan θ
θ = tan^(-1) 0.5
θ = 26.6°
Answer:
52 m/s
Explanation:
Wavelength is the distance between two successive crests. Two crests make one circle hence 16 cycles are equal to 16 wavelengths. Each wavelength is equal to 208/16=13 m long
Speed of wave is given as the product of wavelength and frequency, expressed as
S=fw
Where f is the frequency and w is the wavelength
Substituting 13 m for w and 4 Hz for f then
S=4*13=52 m/s
Therefore, the speed is equivalent to 52 m/s
Use this kinematics equation:
Vf = Vi + aΔt
Vf is the final velocity, Vi is the initial velocity, a is the acceleration, and Δt is the elapsed time.
Assign northward velocity/acceleration as positive and southward as negative. Given values:
Vi = 100km/h = 27.8m/s
a = -4m/s²
Δt = 6s
Plug in the values and solve for Vf:
Vf = 27.8 - 4(6)
Vf = 3.8m/s north
Weight is based on density mass is not.
Considering the frames of reference, the robot has to fire backwards at a speed of 2m/s.
<h3>What is relative velocity?</h3>
The relative velocity is obtained based on the inertial frame of reference. The term velocity is always measured relatively.
Given that the inertial frame of reference is relative to the moving frame then; 7m/s - 9 m/s = -2m/s.
It then follows that the robot has to fire backwards at a speed of 2m/s.
Missing parts:
Basim’s robotics team builds a robot that travels at 9 m/s and can fire a tennis ball at a target.
Which would result in a judge who is sitting beside the testing ground observing the tennis ball having a speed of 7 m/s?
The robot fires the ball forward with a speed of 7 m/s.
The robot fires the ball backward with a speed of 7 m/s.
The robot fires the ball backward with a speed of 2 m/s.
The robot fires the ball forward with a speed of 2 m/s.
Learn more about frame of reference:brainly.com/question/12222532?
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