Answer:
1. 31 Ω
2. 42 Ω
3. V = IR
4. 4 A
5. 1.37 A
Explanation:
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1. "Resistors of 5Ω, 10Ω, and 16Ω are connected in series. Find the total resistance."
The resistance of resistors in series is the sum:
R = R₁ + R₂ + R₃
R = 5Ω + 10Ω + 16Ω
R = 31Ω
2. "The total resistance of two resistors connected in series is 75Ω. The value of one resistor is 33Ω. What is the value of the other one?"
Since they are in series, the total resistance is the sum:
75Ω = 33Ω + R
R = 42Ω
3. "State Ohm's law."
Ohm's law states that a voltage drop across a resistor is equal to the resistance times the current.
V = IR
4. To find the current, we first find the total resistance, then use Ohm's law.
R = 10Ω + 15Ω + 30Ω
R = 55Ω
V = IR
220 V = I × 55Ω
I = 4 A
5. Same steps as before.
R = 1.5Ω + 4Ω + 12Ω
R = 17.5Ω
V = IR
24 V = I × 17.5Ω
I = 1.37 A
