Answer:
1450.4 KN
Explanation:
Pressure = ρhg
where: ρ is the density of the liquid, h is the height and g the force of gravity.
Total pressure exerted by the liquids at the base = Pressure of oil + Pressure of water + Pressure of mercury
So that,
i. Pressure of oil = ρhg
(ρ = 0.8 g/cm³ = 800 kg/m³)
= 800 x 5 x 9.8
= 39200
Pressure of oil = 39200 N
ii. Pressure of water = ρhg
(ρ = 1 g/cm³ = 1000 kg/m³)
= 1000 x 8 x 9.8
= 78400
Pressure of water = 78400 N
ii. Pressure of mercury = ρhg
(ρ = 13.6 g/cm³ = 13600 kg/m³)
= 13600 x 10 x 9.8
= 1332800
Pressure of mercury = 1332800 N
So that,
Total pressure exerted by the liquids at the base = 39200 + 78400 + 1332800
= 1450400
= 1450.4 KN
Total pressure exerted by the liquids at the base is 1450.4 KN.
D. is the correct answer.
Answer:
+ 0.07 C
Explanation:
From the question given above, the following data were obtained:
Potential difference (V) = 12 V
Energy (E) = 0.418 J
Charge (Q) =?
The energy (E) , potential difference (V) and charge (Q) are related by the following equation:
E = ½QV
With the above formula, we can obtain the charge as follow:
Potential difference (V) = 12 V
Energy (E) = 0.418 J
Charge (Q) =?
E = ½QV
0.418 = ½ × Q × 12
0.418 = Q × 6
Divide both side by 6
Q = 0.418 / 6
Q = + 0.07 C
Answer:
The system prevents a consumer from accruing debt via electricity use, as it only allows the customer to use electricity which has been paid for upfront.
this gives the advantage of not allowing the consumer to rack up debt
the disadvantage for the consumer comes when they cannot afford to prepay in a time of financial difficulty - as the system now renders them as having no electricity as well as no money
Answer:
Speed of the cars after the collision is 3.34 m/s.
Explanation:
It is given that,
Mass of one car, m₁ = 1500 kg
Velocity of this car, v₁ = + 30 m/s ( in east )
Mass of other car, m₂ = 3000 kg
Velocity of other car, v₂ = - 20 m/s (in south)
The two cars stick together after the collision. It is a case of inelastic collision. Let v is the speed of cars after collision. It can be calculated using the conservation of linear momentum as :
v = -3.34 m/s
So, the speed of the cars after the collision is 3.34 m/s. Hence, this is the required solution.
