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Assoli18 [71]
3 years ago
13

What are the common Hazard and Risk?​

Chemistry
2 answers:
olya-2409 [2.1K]3 years ago
8 0
<h2><em>What are the common Hazard and Risk?</em></h2>

<em>hello</em><em> </em><em>there </em><em>here </em><em>is </em><em>my </em><em>answ</em>

  • <em>Physical <u>hazards</u> are environmental factors that can harm an employee without necessarily touching them, including heights, noise, radiation and pressure. Safety. These are hazards that create unsafe working conditions. For example, exposed wires or a damaged carpet might result in a tripping hazard</em>

hope it helps

<em>#</em><em>c</em><em>a</em><em>r</em><em>r</em><em>y</em><em> </em><em>on</em><em> learning</em>

<em>mark </em><em>me</em><em> as</em><em> brainlist</em><em> plss</em>

mixas84 [53]3 years ago
7 0

Answer:

A health hazard: Any organism, chemical, condition, or circumstance that may cause injury or illness.

A physical hazard is an agent, factor or circumstance that can cause harm with contact. They can be classified as type of occupational hazard or environmental hazard.

Risks:

Risk is the possibility of a harm arising from a particular exposure to a chemical substance, under specific conditions.

Crossing the street presents the hazard of getting hit by a passing car. But risk is the likelihood of harm actually occurring.

Explanation:

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Which element will chemically combine with fluorine to combine salt?
Natali5045456 [20]

Answer:

When an atom of sodium and an atom of fluorine combine to form the salt, sodium fluoride, an ionic bond, is formed.

Explanation:

8 0
2 years ago
write equations to show the chemical processes which occur when the first ionization and the second ionization energies of lithi
diamong [38]

Answer:

First ionization of lithium:

\text{Li}\;(g)\to \text{Li}^{+} \; (g) + \text{e}^{-}.

Second ionization of lithium:

\text{Li}^{+}\;(g) \to\text{Li}^{2+} \;(g) + \text{e}^{-}.

Explanation:

The ionization energy of an element is the energy required to remove the outermost electron from an atom or ion of the element in gaseous state. (Refer to your textbook for a more precise definition.) Some features of the equation:

  • Start with a gaseous atom (for the first ionization energy only) or a gaseous ion. Write the gaseous state symbol (g) next to any atom or ion in the equation.
  • The product shall contain one gaseous ion and one electron. The charge on the ion shall be the same as the order of the ionization energy. For the second ionization energy, the ion shall carry a charge of +2.
  • Charge shall balance on the two sides of the equation.

First Ionization Energy of Li:

  • The products shall contain a gaseous ion with charge +1 \text{Li}^{+}\;(g) as well as an electron \text{e}^{-}.
  • Charge shall balance on the two sides. There's no net charge on the product side. Neither shall there be a charge on the reactant side. The only reactant shall be a lithium atom which is both gaseous and neutral: \text{Li}\;(g).
  • Hence the equation: \text{Li}\;(g) \to \text{Li}^{+}\;(g) + \text{e}^{-}.

Second Ionization Energy of Li:

  • The product shall contain a gaseous ion with charge +2: \text{Li}^{2+}\;(g) as well as an electron \text{e}^{-}.
  • Charge shall balance on the two sides. What's the net charge on the product side? That shall also be the charge on the reactant side. What will be the reactant?
  • The equation for this process is \text{Li}^{+} \; (g) \to \text{Li}^{2+}\;(g) + \text{e}^{-}.
5 0
3 years ago
Aspirin can be made in the laboratory by reacting acetic anhydride (c4h6o3) with salicylic acid (c7h6o3) to form aspirin (c9h8o4
Temka [501]
V(C₄H₆O₃) = 5.00 mL.
d(C₄H₆O₃) = 1.08 g/mL.
m(C₄H₆O₃) = V(C₄H₆O₃) · d(C₄H₆O₃).
m(C₄H₆O₃) = 5.00 mL · 1.08 g/mL.
m(C₄H₆O₃) = 5.4 g.
n(C₄H₆O₃) = m(C₄H₆O₃) ÷ M(C₄H₆O₃).
n(C₄H₆O₃) = 5.4 g ÷ 102 g/mol.
n(C₄H₆O₃) = 0.0529 mol.
n(C₇H₆O₃) = 2.08 g ÷ 138.1 g/mol.
n(C₇H₆O₃) = 0.015 mol; limiting reactant.
From chemical reaction: n(C₄H₆O₃) : n(C₉H₈O₄) = 1 : 1.
n(C₉H₈O₄) = 0.015 mol.
m(C₉H₈O₄) = 0.015 mol · 180.16 g/mol.
m(C₉H₈O₄) = 2.71 g; theoretical yield.
percent yield od aspirine = 2.57 g ÷ 2.71 g · 100% = 94.83%.

7 0
3 years ago
Why are some examples of a chemical reaction not actually foolproof evidence that of a chemical reaction?13, 8th grade, and I'm
kvasek [131]
So basically, the change in color effects the amount of cations in the solution making it a physical change rather than a chemical one, defying the law of conservation of mass! I hope this helped! (The only time the change in color affects the amount of cations is in the Alkaline Earth Metals)

source: college science teacher 
7 0
3 years ago
What is the molar mass of a substance?
OlgaM077 [116]

oops pls forgive me I accidentally did the wrong question.

4 0
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