Question

There is a 0.40-A current in resistor X when it is connected to a 2.0-V battery. A 0.25-A current is in a second resistor, Y, when it is connected to a 4-V battery. There is a 0.50-A current in a third resistor, Z, when it is connected to a 5.0-V battery. Find the resistor that has the maximum resistance and the resistor that has the least resistance.

Answer 1

We can find the value of the resistance R of each resistor by using Ohm's law:
$V=IR$
where
V is the potential difference across the resistor
I is the current flowing through it

First resistor:
$R_X = \frac{V}{I}= \frac{2.0 V}{0.40 A}=5 \Omega$
Second resistor:
$R_Y = \frac{V}{I}= \frac{4 V}{0.25 A}=16 \Omega$
Third resistor:
$R_Z = \frac{V}{I}= \frac{5.0 V}{0.50 A}=10 \Omega$

So, the resistor with the maximum resistance is the second one (Y), while the resistor with the least resistance is the first one (X)