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zhenek [66]
3 years ago
7

There is a 0.40-A current in resistor X when it is connected to a 2.0-V battery. A 0.25-A current is in a second resistor, Y, wh

en it is connected to a 4-V battery. There is a 0.50-A current in a third resistor, Z, when it is connected to a 5.0-V battery. Find the resistor that has the maximum resistance and the resistor that has the least resistance.
Physics
1 answer:
Katyanochek1 [597]3 years ago
5 0
We can find the value of the resistance R of each resistor by using Ohm's law:
V=IR
where
V is the potential difference across the resistor
I is the current flowing through it

First resistor:
R_X =  \frac{V}{I}= \frac{2.0 V}{0.40 A}=5 \Omega
Second resistor:
R_Y =  \frac{V}{I}= \frac{4 V}{0.25 A}=16 \Omega
Third resistor:
R_Z =  \frac{V}{I}= \frac{5.0 V}{0.50 A}=10 \Omega

So, the resistor with the maximum resistance is the second one (Y), while the resistor with the least resistance is the first one (X)
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Explanation:

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Suppose, In an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is 1.20\times10^{-2}\mu F

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Using formula of resonant frequency

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f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}

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Put the value into the formula

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We need to calculate the impedance of the circuit

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So, Z = R

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Using formula of voltage

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Hence, The maximum voltage is 39.08 V.

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