Answer:
4.65 g x 1 mol/4.0026 g/mol = 1.162 mol helium
Explanation:
Rutherford used gold for his scattering experiment because gold is the most malleable metal and he wanted the thinnest layer as possible. The goldsheet used was around 1000 atoms thick. Therefore, Rutherford selected a Gold foil in his alpha scatttering experiment.
Answer:
The answer to your question is: letter c (96%)
Explanation:
Indium -113 (112-9040580 amu) ₁₁₃In
Indium-115 (114.9038780 amu) ₁₁₅In
Atomic mass of Indium is 114.82 amu ₁₁₄.₈₂In
Formula
Atomic mass = m₁(%₁) +m₂(%₂) / 100
%₁ = x I established this is an equation
%₂ = 100 - x
Substituting values
114.82 = 112.8040x + 114.9039(100-x) /100 and know we expand and simplify
114.82 = 112.8040x + 11490.39 - 114.9039x /100
11482 = 112.8040x -114.9039x +11490.39
11482 - 11490.39 = 112.8040x -114.9039x
-8.39 = -2.099x
x = 3.99
Then % of Indium-115 = 100 - 3.99 = 96
Answer:
A reaction is spontaneous if ΔG is negative.
Explanation:
- The change in free energy (ΔG) is the difference between the heat released during a process and the heat released for the same process occurring in a reversible manner.
- The sign of ΔG gives an indication for the spontaneity of the reaction:
If ΔG is negative, the reaction is spontaneous.
If ΔG = zero, the reaction is at equilibrium.
If ΔG is positive, the reaction is non-spontaneous.
Answer:
Proton and neutrons
Explanation:
they both have a mass of 1 amu or 1 atomic mass