All of the following measure mass except
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The potential difference between the two ends of the circuit is the electric potential difference. The electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.
<h3>What is an electric field?</h3>An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.
The given data in the problem is given by;
E is the electric field = (200 N/C)
d is the distance = 5.0 cm.=0.05 m
Q is the charge of electrons= 1.602 x 10^-19 C
The formula for electric potential is given by;
The work is defined as the product of the potential difference and charge of an electron.
Hence the electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.
To learn more about the electric field refer to the link;