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Fantom [35]
3 years ago
12

When one tectonic plate moves underneath another, what is occurring?

Physics
1 answer:
alexdok [17]3 years ago
7 0
The answer is A. subduction
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(b) During one day, 250 kg of water is pumped through
ser-zykov [4K]

Answer: The energy incident on the solar panel during that day is 9.24 \times 10^{7} J.

Explanation:

Given: Mass = 250 kg

Initial temperature = 16^{o}C

Final temperature = 38^{o}C

Specific heat capacity = 4200 J/kg^{o}C

Formula used to calculate the energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass of substance

C = specific heat capacity

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = 250 kg \times 4200 J/kg^{o}C \times (38 - 16)^{o}C\\= 250 kg \times 4200 J/kg^{o}C \times 22^{o}C

As it is given that water absorbs 25% of the energy incident on the solar panel. Hence, energy incident on the solar panel can be calculated as follows.

\frac{25}{100} \times q = 250 kg \times 4200 J/kg^{o}C \times 22^{o}C\\q = 9.24 \times 10^{7} J

Thus, we can conclude that the energy incident on the solar panel during that day is 9.24 \times 10^{7} J.

4 0
2 years ago
Car 1 drives 20 mph to the south, and car 2 drives 30 mph to the north. From the frame of reference of car 1, what is the veloci
EleoNora [17]
We subtract the velocity of car 1 from the velocity of car 2:
v=(30\ mph\ North)-(20\ mph\ South)
=(30\ mph\ North)+(20\ mph\ North)
=50\ mph\ North
4 0
3 years ago
Read 2 more answers
The distance from the Earth to the Sun equals 1 AU. Neptune is 30 AU from the Sun. How far is Neptune from the Earth? AU
valina [46]

Answer:

The answer is 29 AU

Hoped I helped

mark me as brainliest

4 0
3 years ago
Read 2 more answers
The stopping distance d of a car after the brakes are applied varies directly as the square of the speed r. If a car travelling
Crank
270/70^2  = x/80^2

Cross multiply

270 (6400) = 4900x   

x = 270(6400)/4900

352 and 32/49 feet

Hope this helps


4 0
3 years ago
A 10.0g piece of copper wire, sitting in the sun reaches a temperature of 80.0 C. how many Joules are released when the copper c
Zolol [24]

Answer:

150.8 J

Explanation:

The heat released by the copper wire is given by:

Q=mC_s \Delta T

where:

m = 10.0 g is the mass of the wire

Cs = 0.377 j/(g.C) is the specific heat capacity of copper

\Delta T=40.0 C - 80.0 C=-40.0 C is the change in temperature of the wire

Substituting into the equation, we find

Q=(10.0 g)(0.377 J/gC)(-40.0^{\circ})=-150.8 J

And the sign is negative because the heat is released by the wire.

6 0
3 years ago
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