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3 years ago

In amplitude modulation, which wave property remains constant?

Physics

1 answer:

NNADVOKAT [17]3 years ago

8 0

The carrier frequency remains constant during amplitude modulation. :)

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Patrice walks 4.0 blocks east and then turns north and jogs 6.0 blocks. She then turns west and walks another 4.0 blocks. What i

vivado [14]

Your answer should be D) 14.0 blocks. Hope this helps :D.

4 0

3 years ago

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A car is traveling along a road, and its engine is turning over with an angular velocity of +188 rad/s. The driver steps on the

andreev551 [17]

Answer:

3751.80514 radians

Explanation:

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity

$\alpha$ = Angular acceleration

$\theta$ = Angle of rotation

t = Time taken

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=188\times 15.6+\dfrac{1}{2}\times 0\times 15.6^2\\\Rightarrow \theta=2932.8\ rad$

The angular displacement would be 2932.8 rad

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=293\times 15.6+\dfrac{1}{2}\times 0\times 15.6^2\\\Rightarrow \theta=4570.8\ rad$

The angular displacement would be 4570.8 rad

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{293-188}{15.6}\\\Rightarrow \alpha=6.73076\ rad/s^2$

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\dfrac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\dfrac{293^2-188^2}{2\times 6.73076}\\\Rightarrow \theta=3751.80514\ rad$

Actual value of the angular displacement is 3751.80514 radians

5 0

3 years ago

Where are the three seismographs used to find the epicenter of this earthquake located?

iogann1982 [59]

The seismographs are located in Minneapolis, Detroit, and Charleston.

3 0

3 years ago

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The Gravitron is a ride that rotates around a central axis until it reaches a certain velocity and the riders are pinned to the

Doss [256]

Sounds like you've been given some unnecessary information.
The linear velocity "v" and angular velocity "w" of something in circular motion of radius "R" are related as; 

v = Rw 

You are given v= 15 m/s and R = 3 m , so just solve for "w".

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4 years ago

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. Why must the cyclist accelerate before reaching the hillock?

babunello [35]

Short answer:

So that the cyclist does not slide back down

Long answer:

The main forces a cyclist must conquer are air resistance and gravity. Air resistance increases exponentially with speed. In the switch from cycling on a flat road to hiking a hill, the decreased speed reduces air resistance to the point where drafting other riders offers small benefit. At this point, smaller cyclists, who have finer power-to-weight ratios, will be able to break away from the peloton. Climbing skill can be improved by minimizing weight, and also by pedalling at a constantly elevated rhythm. Large cyclists can attain greater downhill speeds, but on mountainous courses smaller cyclists still have a benefit.

3 0

4 years ago